Hi, I am currently trying to make a part for my user driven website where one user can subscribe to another and whoever they have subscribed to is echoed back on there profile page.
my users table structure is: id username password and my subscription table is: id user_id follow_id
i am currently trying to query the logged in users subscriptions with this sql_query
$subsQuery = mysql_query("SELECT U.username FROM users AS U INNER JOIN subscription AS Sub.follow_id=U.id WHERE Sub.user_id=".$ID); $ID being the logged in users id.
However when trying to echo this on the page using this bit of php:
<? while ($subs = mysql_fetch_assoc($subsQuery)) { ?><br /><br />
<? echo $subs['username'] ?>
<? } ?>
it throws back this error:
Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/avince/public_html/users/user.php on line 53
Any help would be much appreciated!
How to Handle more than one submit button in single form?
HiI have one PHP file which contains one Form. In this form there are two Submit type Buttons<input type="submit" name="edit" value="save"> <input
same querie, or a new one??
Hi guys,I'm still working on this drop down list. I've got the actual drop down list to work (call all the "pname"s from the table, and I've even found how to print the result once you
undefined offset help
Hi All,I kept getting undefined offset PHP notice for a simple for loop. For eg$va = array();$i=0;while($row = mysql_fetch_array($result)){ $va[$i] = $row['id']; $i++;}It gives undefined offset at
Downloading file (Headers)
I'm trying to make users download a file, but they must wait 60 seconds before it begins.But, I'm stuck - the file isn't downloading, and no error is being shown (I've enabled E_ALL error
keeps going back to index.html ???????
ok so i started making my site using mostly.html files now i have added a fair chunk of php. My index,html file had to be renamed to index.php because i am using a include function, I got told that if
Need help: how to catch acess of undefined class properties
Hello. I am learning OO with PHP and have hit a problem.Some code runs as perfectly valid code, where i would like PHP to issue a warning / error.I guess this is because of the loose typing of PHP,
duplicate record notification
In my database, after insertion of records, I want to know if the record inserted is duplicate or not. How can I do this ??
How to display value in drop down list after form has been reloaded
Please bear with me as I am very new to php and html.I have a form with several drop down menus, the one at the top shows a list that when an item is selected fills in the form below including the
Select question
Hi,First I would like to say that php is pretty new for me.. so please don't shoot me if this should be a stupid question!But I'm a little surpized due to following..I have a search script (very large
elseif help!
OK so I'm new to the site, as well as PHP altogether (Trying my hand at managing an online RPG) and so far it's been quite smooth. However whilst trying to change an aspect of the game from giving the