Warning: mysql_num_rows() supplied argument is not a valid MySQL result resource

Posted on 16th Feb 2014 by admin

This may be simple I just may need another pair of eyes..

When i get records back the below code works just fine, when I get 0 rows back it shows the warning below. As you can see I tried to code for it and you can see that the code works as it echo's my message but I want the warning to go away

Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in show_coupon_list.php on line 224
No Coupons for this Catogory or Business. Please let us know about the Category that displayed no results so we can contact businesses for you!

Code: $cat_coupons = mysql_query("SELECT a.business_name, a.seq_id, a.state, a.city
FROM users a where a.seq_id = '$cat_coupons_seq_id'");

Code: $cat_num=mysql_num_rows($cat_coupons);
if ($cat_num > 0)
{
while ($row = mysql_fetch_array($cat_coupons))
{
$business_name = $row["business_name"];
$business_id = $row["seq_id"];
$state = $row["state"];
$city = $row["city"];
echo"<tr>
<td align = 'left'>&nbsp;&nbsp;<a href=show_coupon.php?business=".urlencode($business_name).">$business_name &nbsp;&nbsp;&nbsp; $city,$state </a></td>
</tr>";
}
}
else
echo"<tr>
<td>No Coupons for this Catogory or Business. Please let us know about the Category that
displayed no results so we can contact businesses for you!
</td>
</tr>";

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