why isn't this PHP code working ???

Posted on 16th Feb 2014 by admin

it's suppose to find a name on the database.

<?php

$s = $_POST["lname"];
$x = trim($s);

$exists = false;
$selectedRow = 0;

mysql_connect (localhost,testuser,testuser);
mysql_select_db (testuser);


mysql_query("DROP TABLE myTable");
mysql_query("CREATE DATABASE myDatabase");
mysql_query("USE myDatabase");
mysql_query("CREATE TABLE myTable (firstname VARCHAR(20), " .
"lastname VARCHAR(20), birthdate DATE, dependents INT, ss VARCHAR(11))");
mysql_query("LOAD DATA LOCAL INFILE 'names.txt' INTO TABLE myTable")
or die(mysql_error());

$s = mysql_query("SELECT * FROM myTable ORDER BY lastname");

$rows=mysql_numrows($s);

for($i = 0; $i < $rows; $i++){
$result = trim(mysql_result($s,$i,"lastname"));
if ( strcmp($x, $result) == 0 )
{
$exists = true;
$selectedRow = $i;
}
}

if ($exists == true)
{
$f = mysql_result($s,$selectedRow,"firstname");
$l = mysql_result($s,$selectedRow,"lastname");
$b = mysql_result($s,$selectedRow,"birthdate");
//$d=str_pad(mysql_result($s,$selectedRow,"dependents"), 18, " ");
//$ss=mysql_result($s,$selectedRow,"ss");
print "$f "."$l
Your date of birth is ".$b;
}

else
{
print "$x
Your name is not listed";
}

mysql_query("DROP DATABASE myDatabase") or die(mysql_error());
mysql_close();
?>

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