Well i am quite new with PHP
and for school we have to make a PHP script which reffers to a Database,
Well, more explicit, we have this form showing all "employees"
last name etc.
made it week before,
and we had to add a new bar to also upload pictures and show them.
So i made this script but it won't work.
And maybe it's just me being stupid..
But please help me
EDIT: it's obvious that pictures reffers to the picture iwant to upload and show.
2nd EDIT: Found out i missed a " , "
Well now the problem is that when i run it and try to upload a picture i won't see anything
<?php
function displayAllEmployees() {
$sql = "SELECT * FROM `Employees` ORDER BY `LastName`";
$result = mysql_query($sql);
echo"<h1>Werknemers</h1>";
echo"<br/>";
echo"<input type="button" onclick="document.location.href='?action=addemployee';" value="Werknemer toevoegen" />";
echo"<br/>";
echo"<br/>";
echo"<table>";
echo" <tr>";
echo" <th>Employee ID</td>";
echo" <th>Last Name</td>";
echo" <th>Phone Number</td>";
echo" <th>Foto</td>";
echo" <th>Actie</td>";
echo" </tr>";
while($row = mysql_fetch_assoc($result)) {
$row = escapeArray($row);
echo" <tr>";
echo" <td>".$row['EmployeeID']."</td>";
echo" <td>".$row['LastName']."</td>";
echo" <td>".$row['PhoneNumber']."</td>";
echo" <td>".$row['Picture']."</td>";
echo" <td>";
echo" <a href="index.php?action=editemployee&id=".$row['EmployeeID']."">Bewerken</a>";
echo" |";
echo" <a href="javascript:confirmAction('Zeker weten?', 'index.php?action=deleteemployee&id=".$row['EmployeeID']."');">Verwijderen</a>";
echo" </td>";
echo" </tr>";
}
echo"</table>";
}
function displayAddEmployee() {
echo"<h1>Werknemer bewerken</h1>";
echo" <form method="post" action="index.php?action=insertemployee">";
echo" <table>";
echo" <tr>";
echo" <td>werknemernummer:</td>";
echo" <td><input type="text" name="EmployeeID" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>achternaam:</td>";
echo" <td><input type="text" name="LastName" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>telefoonnummer:</td>";
echo" <td><input type="text" name="PhoneNumber" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>Foto:</td>";
echo" <td><input type="file" name="Picture" /></td>";
echo" </tr>";
echo" <td></td>";
echo" <td><input type="submit" value="Opslaan" /></td>";
echo" </tr>";
echo" </table>";
echo" </form>";
}
function displayEditEmployees() {
$sql = sprintf( "SELECT * FROM `Employees` WHERE `EmployeeID` = %d",
mysql_escape_string($_GET['id']) );
$result = mysql_query($sql);
if($row = mysql_fetch_assoc($result)) {
$row = escapeArray($row);
echo"<h1>Werknemer bewerken</h1>";
echo" <form method="post" action="index.php?action=updateemployee">";
echo" <table>";
echo" <tr>";
echo" <td>Titel:</td>";
echo" <td><input type="text" name="EmployeeID" value="".$row['EmployeeID']."" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>Achternaam:</td>";
echo" <td><input type="text" name="LastName" value="".$row['LastName']."" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>Telefoon Nummer:</td>";
echo" <td><input type="text" name="PhoneNumber" value="".$row['PhoneNumber']."" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>Foto:</td>";
echo" <td><input type="text" name="Picture" value="".$row['Picture']."" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td></td>";
echo" <td><input type="submit" value="Opslaan" /></td>";
echo" </tr>";
echo" </table>";
echo" <input type="hidden" name="EmployeeID" value="".$row['EmployeeID']."" />";
echo" </form>";
}
else {
die("Geen gegevens gevonden");
}
}
function addEmployee() {
$sql = sprintf("INSERT INTO `Employees` (`EmployeeID`, `LastName`, `PhoneNumber`) VALUES ('%s', '%f', '%f', '%f')",
mysql_escape_string($_POST['EmployeeID']),
mysql_escape_string($_POST['LastName']),
mysql_escape_string($_POST['PhoneNumber']),
mysql_escape_string($_POST['Picture']) );
mysql_query($sql);
header("location: index.php?action=employees");
exit();
}
function updateEmployees() {
$sql = sprintf("UPDATE `Employees` SET
`EmployeeID` = '%s',
`LastName` = '%s',
`PhoneNumber` = '%s'
`Picture` = '%s'
WHERE `EmployeeID` = %d",
mysql_escape_string($_POST['LastName']),
mysql_escape_string($_POST['PhoneNumber']),
mysql_escape_string($_POST['EmployeeID'])
mysql_escape_string($_POST['Picture']) );
mysql_query($sql);
header("location: index.php?action=employees");
exit();
}
function deleteEmployees() {
$sql = sprintf("DELETE FROM `Employees` WHERE `EmployeeID` = %d", mysql_escape_string($_GET['id']));
mysql_query($sql);
header("location: index.php?action=employees");
exit();
}
?>
Timer control causing error
I recently decided to add a timer control to an existing page that uses AJAX on my site. As soon as I added the timer control and ran my app, I started getting the following error:Description: An
shift numbers with paging
HiHow would i be able to display 10 numbers 1 2 3 4 5 6 7 8 9 10 and when I click next then 2 3 4 5 6 7 8 9 10 11 and click next then 3 4 5 6 7 8 9 10 11 12are displayed.i am using a for loop to echo
Tracking Unique Clicks
Hi guys and gals,Basically I have a database which tracks clicks on my outbound links, I do this by linking to a page like so.../redirect.php?id=1The page then reads the id and increments the click
How to separate records and ORDER BY
Let say i have 100 records and displayed in one page, then i want to get the records from 50-100 and use ORDER BY to re-order whether DESC or ASCHow can i do the ORDER BY without re-order first 50
Displaying image from database
Hi,I've got a site where that's got a database behind it. Currently it has loads of items in rows that all have different pictures. There is a field called "Image" that has the name of the
Send current URL in URL with a $_GET variable problem.
Hello community,I have created a function that gets the current variable of a page, example:current page URL: Code: [Select] http://example.com/activate.php?token=123&code=321Now, I want to
Array to string conversion
Can anyone help me with this?Notice: Array to string conversion in /home/..../index.php on line 360Whatever this is, it's causing the script to fail at uploading.Code (starting just before line
need help about
i store the value of my select statement result to an array and stored it to a variable named $fname the i used it as the value of:<input type='text' name='fname' value=<?php echo $fname
Auto install
Hi I have a directory lets say "apps" that I then have more folders ie "email", "projectmanagment" now each of these "apps" need a mysql table, each of these
PHP and Javascript
Hi Guys,Im trying to load the contents of an html file into a text area for editing, this is the code I have so far but it doesnt seem to be working. I think it's because some of the $line have