do while conditions

Posted on 16th Feb 2014 by admin

i want to display 6 images in a 2x3 table
now what would be the correct logic to
count that there are 6 images results
and if there are more than 6 images loop and echo the rest but not in the table
but as links?

the idea is to have 6 thumbnails and then a large images in a gallery

this is what i played with it gives me the table i want , how should i add the additional condition - echo the remaining inages after the 6th??

Code: <table>
<tr>
<?php
$RsImage_list_endRow = 0;
$RsImage_list_columns = 2; // number of columns
$RsImage_list_hloopRow1 = 0; // first row flag
do {
if($RsImage_list_endRow == 0 && $RsImage_list_hloopRow1++ != 0) echo "<tr>";
?>
<td width="85"><a href="/images/<?php echo $row_RsImage_list['imagename']; ?>" rel="lightbox[<?php echo $row_RsImage_list['ProductID']; ?>]"><img src="<?php echo $row_RsImage_list['imagename']; ?>" width="85" height="64" border="0"/></a></td>
<?php $RsImage_list_endRow++;
if($RsImage_list_endRow >= $RsImage_list_columns) {
?>
</tr>
<?php
$RsImage_list_endRow = 0;
}
} while ($row_RsImage_list = mysql_fetch_assoc($RsImage_list));
if($RsImage_list_endRow != 0) {
while ($RsImage_list_endRow < $RsImage_list_columns) {
echo("<td>&nbsp;</td>");
$RsImage_list_endRow++;
}
echo("</tr>");
}?>
</table>

Other php-forum