Hey everyone, I am using JQuery in several sites so I thought it would be best to place the library reference in the masterpage. It works great everywhere, except when my javascrip is called from inside a particular user control. Without the JQuery library reference, the javascript wont pop up at all. With the reference the javascript pops, but the functionality of the script is shakey at best. I have narrowed the issue down to things within the javascript that begin with the $ symbol. Thos items do not work, anything that makes a function call still works. I am not great with JS or JQ as I am just doing the code behind on what someone else did for the UI. Any thoughts would be much appreciated.
include function being weird?
I have a very simple system to grab an IP outputted by a PHP file.. (for a project I have) but it outputs a 1 at the end!!<form method="post" action="<?php echo
PHP Search Issue
Hi, I am using the following code to search and return flights from a database. The user searches by inputting a DepID and an ArrID and I want to display only flights that match both DepID and ArrID.
if else problem, help please
i have this script that i made only i try to also put in a if else for for some reason the script is not putting out the else echo. its not really a problem as the script works but it would be nice to
How to replace search button with link?
hi to everbody.i have a search submit form and button like this :<form id="f1" name="title" method="post"
Text file to .Dat file Conversion in PHP
Hi All, Could anybody provide code for Text file to .Dat file Conversion in PHP. Thanks,
PHP friend keyword equivalent
is there a PHP equivalent for the C++ friend keyword?
Passing JS to PHP
So I have the followingCode: <?phpgetdetails(?><script type="text/javascript">document.write(jsvariable)</script><?php );?>The idea is
Somebody hacked into my site and changed coding >>> URGENT HELP NEEDED <<<
I am not that much into programming , but somebody is hacking to my site and injecting some kind of iframes ... it happened to another site , but that wasn't that important for me, but now it has
Warning: mysql_num_rows() supplied argument is not a valid MySQL result resource
This may be simple I just may need another pair of eyes..When i get records back the below code works just fine, when I get 0 rows back it shows the warning below. As you can see I tried to code for
Form a inline view based on the results of the previous query?
Hi Experts,