I have a while loop to get image names.
Code: $imagequery = mysql_query("SELECT * FROM ad_image WHERE user='$user' AND ad='$adnr' ORDER BY `picorder` ASC")or die(mysql_error());
$totpics = mysql_num_rows($imagequery);
while ($imageset = mysql_fetch_array($imagequery)){
$order= $imageset['picorder'];
$image= $imageset['image'];
$title= $imageset['title'];
$imagesize = getimagesize($modx->config['base_path'].'ad_images/'.$image);
$height = $imagesize[1];
}
How do I get the highest number of $height as
Code: $array = array($height);
echo max($array);does not work?
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this code is not working????
it says this error.. Warning: Division by zero in ..the variables are correct, so why is the variable $max zero??/Code: $sw = $_GET['w']; $sh = $_GET['h'];
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Please disregard..........I figured it out
what business processes?
Hi,