Hi, does php have any functionality that enables a programmer to extract information from a website on the internet and display it on their own? Any help or suggestions on where to go and look for a solution will be much appreciated.
value not going in data base
hello friends.... i am having a working javascript....when i am selecting any designation and refresh/validation problem the form is resetting the designation value and the
Material Master Update through BAPI - Follow up material not updated
Hi Experts,
how to remove in php string display
My code is$message="We're looking at developing our website.";$body= "My message is,\n\n\n\n\t\t\t".$message";echo $body;I get result We\'re looking at developing our
[newb] Image hosting help.
Hey there, I'm new to php, I know some basics and i can code PWN, I'm only 14 but I'm interested in PHP, I have bought a dedicated server, (With unlimited bandwidth of corse, And 2tb Hard drives), And
PHP webpage & array print issue
I have this code running, and it works perfectly … however, see my bottom bit about what I see when I view source, versus what I want to see … I am having image re-sizing issues that
problems with script
I made a small script wich exchanges points in my website: <?phpsession_start();include_once"config.php";$username = $_SESSION['username']; if(isset($_POST['exchange'])){$spoints =
Need help PLEASE
ok i have this warning showing upWarning: in_array() [function.in-array]: Wrong datatype for second argument in /home/lalala/public_html/attack.php on line 72the code i use Code: [Select]//same ip
On page view, minus credit
Hello all, please, I need a little help with this script. I am charging one credit (credits can be purchased, but that is unrelated) for view of a certain page. I need help in figuring out what php I
A little help needed passing hidden values to next page
I have a page that has hidden values in a form.exampleCode: <input name='signupID' type='hidden' value='1' /><input name='signupID' type='hidden' value='2' /><input
use an array from 1 class in a second class
I have a class that adds data to an arrayThen I have a second class and I need to check if the data it returns is in the array created in the first class.But I get undefined variable: Array
