Hello i got this code to fetch data from database but it is not working it displays
7
Array
Array
Array
Array
Array
Array
Code: if (isset($_POST['showrecord']))
{
$query='SELECT * FROM artus_test';
$result=mysql_query($query);
$numrows=mysql_num_rows($result);
while($row = mysql_fetch_assoc($result)){
$mypdata[] = $row['test_id'];
$mypdata[] = unserialize($row['organ']);
$mypdata[] = unserialize($row['design']);
$mypdata[] = unserialize($row['start_month']);
$mypdata[] = unserialize($row['start_year']);
$mypdata[] = unserialize($row['end_month']);
$mypdata[] = unserialize($row['end_year']);
foreach ($mypdata as $value) {
echo $value."<br/>";
}
}
}
help me please
How to Create a Dynamic table
col1 col2 date1 date2 date3 date4..........a b v1 v2 v3 v4c d v5 v6 v7 v8e f v9 v10 v11 v12 . .
Undefined index: username HELP NEWBIE
I am trying a simple login/logout for my website. It works well with checking if the username exists in the database to logging in. I used $_SESSION['username']=$myusername; However, when I log-out,
Notice Undefined index: reset/ Attempting to redirect, works, but get a notice
Full Header.php is:Code: [Select]<?php$reset= false;$reset= strip_tags($_GET["reset"]); //THIS IS LINE 3if(empty($reset)) $reset = false;if($reset==NULL)
Echo Tweaking help!
HI. I would like to have the output of the entered variables repeat forever, but it's stopping at the last entered variable. Help would be great! <html><head>
CHECH A STRING FOR ' " ' (DOUBLE QUOTES)
I am checking for delimiter (.!?) and if there is a " after a sentence then it should neglect and start from next sentenceI am splitting into two sentences"This is first sentence." This
Data Function is Its Not working IN IE8
This is my first time to use formums. I hope i can get solution for this problem.
UPLOAD IMAGES NOT WORKING!
Hi there i have a upload script in which it uploads the picture to a folder than creates two thumbnails in different folders however it is uploading the image and saving it in the folder /photos/ then
Connecion issue
Hi,For some reason, I keep getting this error when trying to connect:Warning: mysql_connect() [function.mysql-connect]: Can't connect to MySQL server on...Warning: mysql_select_db()
parse error
On my local machine I keep getting parse error for my footer. When I put it online, it doesn't show anything.I've searched on google but not found a solution for it. The error message:Parse error:
getting a website's source code as a variable? How?
Hey guys, is there any way for me to get the source code of a website as a variable for me to work with?Ex:$url="http://www.google.com"$sourcecode=magicfunction($url);//so that i could