hi i have one form. there are three fields which are to be filled by the user. and then there are two buttons. ob clicking first button i want to save user's provided data to the database display the same page again. and on clicking second button the provided data will be saved and will be taken to next page.
my problem is with these buttons how can i set up these buttons to do the the action?
my code is here
Code: [Select]<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Untitled Document</title>
</head>
<body>
<form name="form1" method="post" action="">
<label>Degree Name:
<input type="text" name="textfield" id="textfield">
</label>
<p>
<label>CGPA:
<input type="text" name="textfield2" id="textfield2">
</label>
</p>
<p>
<label>Institute:
<input type="text" name="textfield3" id="textfield3">
</label>
</p>
<p>
<label>
<input type="submit" name="button" id="button" value="Save And Add Another">
</label>
</p>
<p>
<label>
<input type="submit" name="button2" id="button2" value="Save And Proceed to Next Step">
</label>
</p>
</form>
<?php
$db = mysql_connect("localhost");
mysql_select_db("job", $db);
$addcv = mysql_query("insert into cv
(
degree,
cgpa,
institute
)
values
(
'".$degree."',
'".$cgpa."',
'".$institute."',
)");
echo "Your data is added.";
?>
</body>
</html>
CODE NOT WORKING
Code: [Select]<?php//include shared codesinclude '../lib/common.php';include '../lib/db.php';include '../lib/function.php';include '../lib/User.php';//construct password request for
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