Hi all,
I would like to have a form that gives you options based on the results of an mysql query.
My example is this, say I have a mysql row with the colum name points and the result is 5. How would I populate a form with a drop down box with the options 1 or 5. Ie the user can select either a single point they have or all 5?
need help in update query
hi i have a dynamic form. i need help in how can i use update query when values from dynamic form get pass to php file.currently when i press submit it displays this and does not update fieldsCode:
Login page problems
I developed a website a few months ago and I am now having an issue with logging into it. The place that it is hosted just did some upgrades to their servers and for some reason, now my login page
how do i display data on a page from mysql
1 - do i use this code at the top of each of my page i wish to only alow access if there as been a sessionCode: <?phpinclude_once 'Connect.php';if (!is_authed()) { die ('You are not
upload form file types....
Hey all, I am learning PHP and I am writing a script from the W3C Schools tutorials for uploading files to my server. I want to be able to use it for a friend to upload files to my server (I know to
Automatic Webpage ??
I have a page www.mysite.com/test.php with a <form> <textarea name="data" cols="100" rows="20"></textarea> //to enter the
Populate drop down list from table??
Lets say for arguments sake that i have a table which contains the numbers 1 to 10.How can i get a drop down list to pull these numbers from the table?So if i then added more numbers to the table then
my login script page is not working on remote computers
hi my login is working on my computer, but when i tried 2 computers from 2 different locations, they couldnt login. any help greatly appreciated. thanks. derek. its setting the hack variable to Y on
Business Health Check
Hello I need to create an online business health check for a client it will be multiple choice and about 50 questions but the client has requested that the output/results of the health check needs to
Spaghetti Code
So.I've pretty much reached the point where I have so many isset s on one page that I can't tell what the page is supposed to do. In other words: spaghetti code. I just read a few tutorials on OOP,
post to self
Trying to get my form to submit to itself. However I am also trying to use an image for my submit button, when I set the type='image' it will not submit to itself. Can someone help me figure out
