Hi,
I am a total newbie to PHP. I am also a unemployed and need to get a job. So after 100% rejection rate for job applications since last November, I have built me a little 'self-marketing' site with a prebuilt email contact form in it. The form design fits in just perfectly in terms of CSS and size. I want to retain it so I got hold of a basic online generated form.
I uploaded and tested the online generated basic three field name, email and comment form and feedback. php to ensure my host's systems would permit the html form to work and that I'd receive an email at my Outlook Inbox. The tests worked perfectly.
So I swapped over the feedback.php and html scripts to the forms I had generated based on the basic & to which I had added two extra fields - phone and company. I tested. Nothing happens. No error message. No thank you. No email. Zilch.
I have spent days searching for a blatant fault and retrying different formats resulting in abject failure. I need expert help.
I am unable to decipher the php or html (index-4.html) to find my errors, and so will be most grateful if one of you experts would please take a look at the files attached to this post. I will be pleased if you'd locate where I have screwed things up and tell me how to rectify the html form and php. I need to get the email working because the site is where I will push potential employers to go and see me and read some of my experience and then to hopefully email me to send them my CV to get that all important interview.
The site is at http://rbruce.org. The domain is a subdomain. The directory is located at the true root of the main domain called p45camp.com. I had the rbruce.org folder located under public_html but the host's, Namecheap.com, relocated it to its current location and for some reason the folder is now called rbruce.new. But it works if you point your browser to rbruce.org
Your help will help me start getting the responses I need. And that'll be a good thing for my bank overdraft and my family's future.
Thanks in advance
Read from a text file after a specific word
Hi all. I have a text file that looks like the one below. I know how to open the text file but I need to get the php pointer to take a value suck as $username. Once it finds $username, i need it to
How do I get the row number from from an sql table query
Hi allI have a table that I query and it returns a number of rows.mysql_num_rows($query) = $totalI want to have next and previous buttons, is there a way of retrieving the current row number, and can
Add code to enable passing of checkbox variable on login
Ok, I have a login page, but want to add a checkbox that when checked and successful login is made it passes the checkbox value (checked = "Yes" to the next page) which then loads password
Inserting Data into a MS Access DB using PHP.
As part of my uni course I am doing a placement at a company whom want me to create a client zone for their website.Basically, they want me to create the code to get data from a MS Access db and
textfield unchanged
hi,i want my form to know whether its textbox is unchange or not.if($textbox == 'unchanged'){ //do this}else{ //do this}ive been searching all day , but cant find the exact solutions...
array & querys help/advice.
Ok so here goes , I have a mysql database and basically here's what I need to do.// foreach store id// foreach product id {// query with where store id and product id// get price row for each
Problem assigning value to variable in "IF" function
Does this script makes sense? I am trying to take the value that is set to "authenticat" and write it to authentication.I think it is getting messes up by the $authenticat = "1"
Php mysql - select?
Hi i have this code:Code: $iteminfo = mysql_query("SELECT desc FROM wc_items WHERE itemid = '$_GET[id]'") or die(mysql_error()); And it gives meYou have an error in your SQL syntax; check
values not being entered into table
hi. I;ve created a form, so that when a user enters data into it, it gets added to a table in a database. the form submits some data to one table, and other data to another table. my problem is that
having a small php error tha deals with the 'foreach'
Last night i was working on a script for a cart and it seemed to working good, until this morning. For some reason i'ts giving me the following error:Warning: Invalid argument supplied for foreach()