values not being entered into table
Posted on
16th Feb 2014 07:03 pm by
admin
hi. I;ve created a form, so that when a user enters data into it, it gets added to a table in a database. the form submits some data to one table, and other data to another table. my problem is that the data only gets added to the first table, but data doesnt enter correnctly into the other one.
Code: <?PHP
$questionno = $_POST['questionno'];
$question = $_POST['question'];
$quizref = $_POST['quizref'];
$answerno = $_POST['answerno'];
$answer = $_POST['answer'];
$answervalue = $_POST['answervalue'];
pg_connect("host=database.*******.uk
port=5432 dbname=***** user=***** password=******");
?>
<html>
<head>
<title>Add </title>
</head>
<body>
<?php
$query="INSERT INTO questions (questionno, question, quizref)VALUES ('".$questionno."', '".$question."', '".$quizref."')";
pg_query($query) or die ('Error adding new question');
echo "The question has been added to the quiz";
$queryanswers="INSERT INTO answers (answerno, answer, answervalue, questionno, quizref)VALUES ('".$answerno."', '".$answer."','".$answervalue."', '".$questionno."', '".$quizref."')";
pg_query($queryanswers) or die ('Error adding new answers');
echo "The answers has been added to the question";
?>
<form method="post" action="">
quizref: <br/>
<input type="text" name ="quizref" size="5" /><br/>
Question Number: <br/>
<input type="text" name="questionno" size="5" /><br/>
Question: <br/>
<input type="text" name="question" size="60" /><br/>
Answers<br/><br/>
Answer number:<br/>
<input type="text" name ="answerno" size="5" /><br/>
Answer<br/>
<input type="text" name ="answer" size="60" /><br/>
Answer value<br/>
<input type="text" name ="answervalue" size="5" /><br/>
<br/><br/>
Answer number:<br/>
<input type="text" name ="answerno" size="5" /><br/>
Answer<br/>
<input type="text" name ="answer" size="60" /><br/>
Answer value<br/>
<input type="text" name ="answervalue" size="5" /><br/>
<br/><br/>
Answer number:<br/>
<input type="text" name ="answerno" size="5" /><br/>
Answer<br/>
<input type="text" name ="answer" size="60" /><br/>
Answer value<br/>
<input type="text" name ="answervalue" size="5" /><br/>
<br/><br/>
Answer number:<br/>
<input type="text" name ="answerno" size="5" /><br/>
Answer<br/>
<input type="text" name ="answer" size="60" /><br/>
Answer value<br/>
<input type="text" name ="answervalue" size="5" /><br/>
<br/><br/>
<input type="submit" value="Send and Add another Add Questions" />
<a href="addfinish.php"><input type="submit" value="Add and finish" /></a>
</form>
</body>
</html>
Any help would be great.
thanks
No comments posted yet
Your Answer:
Login to answer
315
28
Other forums
parsing error
can anyone explain this syntax error:
Parse error: syntax error, unexpected T_IF
The e
Create or replace package is ending ORA-21700
Database 9.2.0., patch 8 (9.2.0.8.0).
I trying run
create or replace package ....etc.
scandir clients directory
hi,
how can i scandir the clients directory? i need a script that when i click a button it will u
parse error
On my local machine I keep getting parse error for my footer. When I put it online, it doesn't show
webpage with (simple) login & mysql-db
Hi all,
What I was looking for before was a multi-user password manager, web-based! The offer
Wierd echo error?
Hi, i got the most wierd php error ever and i don't know why..
Code: echo "<t
a dificult string search
Hi I don't know a way around this. I want the user to input a password, but to make it a bit complca
disable all input buttons
Hello Friends,
suppose i do have a file ( file.php ) has a submit button
Code: [Sele
Retrieving innerHTML with cURL?
Hey all (sorry I know I'm a leecher, but I soon won't be. This is my first PHP project, but not my l
mysql UNION | warning mysql_fetch_array !!
Code: <?php
$i = 0;
$query1="SELECT * FROM `products` WHERE `div