LIMIT $start, 10... how to pass last value queried into next page with GET??

Posted on 16th Feb 2014 by admin

Ok I know how to display the first or last 10 results of a query...

$result = mysql_query("SELECT * FROM messages ORDER BY timemsg DESC LIMIT 10");

In a perfect world all the rows ID's would be in perfect order (i.e.- 10,9,8,7,6,5,4,3,2,1), so to display messages 30 to 40 I would just do LIMIT 30,10
but because of certain unforseen situations the actual results will end up being more like-
457
455
454
453
449
448
447
419
418
410

So I can display the last 10 results in descending order but then to show the "previous 10" results (using the above numbers for an example), I'm thinking I need to somehow
capture the last result in this query (410) so when you hit "previous 10" link it passes it through GET to the next page and the next page will use something like LIMIT $start,10
to display the 10 results with before "410" and so on. Any idea how to do this, I don't think it should be that hard, just can't figure it out. Sorry, if this is in wrong thread,
feel free to move to MYSQL board if it belongs there.. Thanks for any help!

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