User input in to variable

Posted on 16th Feb 2014 by admin

Hi all,

I'm sure this is very easy but I'm having another brain freeze!

At the end of the code I have echoed 3 bits of info to screen $ip, $_POST['ssid'] and $ssid_id".

I would like to put $_POST['ssid'] into a variable, is this possible?

Jamie

Code: <?php
//run site query
require("confwifi.php") ;
{
$ext_site = $_POST['site'];

$extract = mysql_query ("SELECT * FROM site WHERE site='$ext_site'");
$numrows = mysql_num_rows ($extract);

while ($row = mysql_fetch_assoc($extract))
{
$id = $row['id'];
$site = $row['site'];
$ip = $row['ip'];
}

}

?>

<?php
//run site query
require("confwifi.php") ;
{
$ext_ssid = $_POST['ssid_name'];

$extract = mysql_query ("SELECT * FROM ssid WHERE ssid_name='$ext_ssid'");
$numrows = mysql_num_rows ($extract);

while ($row = mysql_fetch_assoc($extract))
{
$ssid_id = $row['ssid_id'];
$ssid_name = $row['ssid_name'];

}

}

?>


<form name="form1" method="POST" action="wifichange.php"><div>

<select name="site">
<option value="0" selected>(please select:)</option>
<option name="site">Llandaf</option>
<option name="site">Cyncoed</option>
<option name="site">Howard Gardens</option>
<option name="site">Colchester Avenue</option>
</select>


<select name="ssid_name">
<option value="0" selected>(please select:)</option>
<option name="ssid_name">Guest</option>
<option name="ssid_name">Conferences</option>
</select>
</form>
<p><input type="text" name="ssid"></div></P>

<div><input type="submit" value="submit"></div>
</form>




<?php echo "$ip"; ?><p></p>

<?php echo $_POST['ssid'];; ?><p></p>

<?php echo "$ssid_id"; ?><p></p>

<?php