<?php
function dosomething($string, $else = '') {
if (empty($else))
$string = "<b>$string</b>";
else
$string = "<i>$string</i>";
return $string;
}
$input = "Some words.
[code]some code.[/code]
More words.
[quote]some code[/quote].
Other words.";
$codetag = array('[code]', '[quote]');
$codetag_rev = array('[/code]', '[/quote]');
for ($i = 0; $i < count($codetag); $i++)
$codetag_array[] = "/([sS]*$codetag[$i])([sS]+)($codetag_rev[$i])([sS]*)/e";
$input_new = preg_replace($codetag_array, 'dosomething("$1") . dosomething("$2","else") .dosomething("$3") . dosomething("$4")', $input);
echo "$inputn<hr>n$input_new";
// This becomes a huge mess and $2 doesn't get saved from being bold
echo "<hr><hr>";
// It does work fine if I only try it on one tag
$input_new = preg_replace($codetag_array[0], 'dosomething("$1") . dosomething("$2","else") .dosomething("$3") . dosomething("$4")', $input);
echo "$inputn<hr>n$input_new";
// $2 is indeed saved from turning bold
?>
So my only question is - how do I do this for multiple tags?
Or, if you want, you can simply ignore everything until now and just tell me how do I turn $input into:
// Output:
<b>Some words.
[code]</b><i>some code.</i>[/code]<b>
More words.
[quote]</b><i>some code</i><b>[/quote].
Other words.</b>;
Thanks
How to display value in drop down list after form has been reloaded
Please bear with me as I am very new to php and html.I have a form with several drop down menus, the one at the top shows a list that when an item is selected fills in the form below including the
Structure Question - One Table or One Table Per Record Set?
I have a web app (mySQL and PHP) which allows people to create an item with up to 200 records which I store in a single table. Any user subscribing to that item will be pulling up to 4 records from
Changing files over
Just thought I'd start with the new forums looking really nice .Ok basically I've made this site www.sampleestateagent.com and the CMS and search function is all done for the buying part of the site.
Code Review - SQL and Insertion Attacks (Warning: Not for Newbs)
Hey guys,Its been a while, I know. Use to love coming here to answer peoples questions, but work and school have been keeping me too busy but do anything but lurk. I usually write all my code/apps by
Oracle11g Patch issue
Hi all,I'm getting the following error while installing Oracle11g Patch 11.1.0.7.0 on IBM-AIX/oracle/Disk1/stage/Components/oracle.owb.rsf/11.1.0.7.0/1/Datafiles/filegroup16.jar.when I look into the
File upload issues
Hi Guys,Can anyone see any issues with this code:Code: [Select]$setImage= 'productimages/' . date(U) . $HTTP_POST_FILES['setImage']['name'][0];copy($HTTP_POST_FILES['setImage']['tmp_name'][0],
Just cannot get 'area' to submit to db using same php code as already used
Basically all i have done is just modified some code and added an area section.The form is allready submitting other things like location price etc.And i have simply added a field in db called area
returning data from an ssh2_exec()
here's what i got.$conn = ssh2_connect($this->_host); ssh2_auth_password($conn,$this->_user,$this->_pass)or die("Cannot Connect"); //build command line to include
pull content
I have an existing page, domain/adverts.php which has a good PR. I've just rebuilt my site and the new version of that page is now a couple of folders deep, at domain/subfolder/adverts/ads.php. I've
check if value exists
I have googled this for a while and I am getting lots of different results. Is there a standard method used for checking to see if a value exists in a database before inserting a value? I have a form,