IF Statement & Two Tables With Different Echoes

Posted on 16th Feb 2014 by admin

I'm retrieving two tables in a single query using UNION ALL, like so:

Code: $query = "SELECT * FROM film UNION ALL SELECT * FROM people ORDER BY id DESC LIMIT 5 ";
Now each of those tables, FILM and PEOPLE create links to two different pages for the different information stored in the said tables. Here are the two different echoes for the tables:

FILM:
Code: <li><a href="filmography.php?title='.$title.'"><img src="images/thumbnails/'.$image.'.jpg" alt="" title="'.$title.' ('.$year.')"></a></li>
PEOPLE:
Code: <li><a href="biography.php?name='.$name.'"><img src="images/thumbnails/'.$img.'.jpg" alt="" title="'.$name.' ('.$occupation.')"></a></li>
Is there an IF statement, or anything else for that matter, which will identify which table each row comes from and then assign the necessary link to that row, like so?:

Quoteif (row belongs to (FILM)) {
echo '<li><a href="filmography.php?title='.$title.'"><img src="images/thumbnails/'.$image.'.jpg" alt="" title="'.$title.' ('.$year.')"></a></li>';
}
else echo '<li><a href="biography.php?name='.$name.'"><img src="images/thumbnails/'.$img.'.jpg" alt="" title="'.$name.' ('.$occupation.')"></a></li>';
Here's my poor attempt at managing it (obviously doesn't work):
Code: <?php

mysql_connect(localhost,user,pw);
@mysql_select_db(db) or die( "Unable to select database");

$query = "SELECT * FROM film UNION ALL SELECT * FROM people ORDER BY id DESC LIMIT 5 ";
$result = mysql_query( $query ) or die(mysql_error());

while ($row = mysql_fetch_array($result))
{
extract($row);

$field_array = mysql_fetch_array($result);
if (!in_array(`img`, $field_array)) {

echo '<li><a href="filmography.php?title='.$title.'"><img src="images/thumbnails/'.$image.'.jpg" alt="" title="'.$title.' ('.$year.')"></a></li>';

}
else echo '<li><a href="biography.php?name='.$name.'"><img src="images/thumbnails/'.$img.'.jpg" alt="" title="'.$name.' ('.$occupation.')"></a></li>';

}
?>

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