I am new with php and here is a simple guessbook page but I am being hit with spam from a group of the same email. I know I need to do an IF statement but I am kinda foggy on how to do the code.
What I want to do is make an file that has email address that I want to block and code to call it up to make sure the people that are signing it is not one of the spamers.
Here is my code for the page. Just need help on where to nest the code to call up the blocked email to stop them from posting.
Also if any one knows how to disable html coding from being displayed as well would be helpful.
Line number On/Off | Expand/Contract <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"><head> <title>Feed Back</title> <? include "data/head.php"; ?><body><center><table width="700" border=".01" cellspacing="0" cellpadding="0"><tr><td height="182" align="center" valign="bottom"><P ALIGN=CENTER><P ALIGN=CENTER><IMG SRC="Images/title/feedback2.gif" NAME="graphics10" ALT="About Me" ALIGN=BOTTOM WIDTH=500 HEIGHT=100 BORDER=0>
</p> <?php include "data/menu.php"; ?></td></tr><tr><td height="1050" align="left" valign="top"> <center><h2>Feedback Form</h2></center> <p>Share your feedback with me.</p> <form method="post" action="feedback.php"> <label for="firstname">First name:</label> <input type="text" name="firstname" /><br /> <label for="lastname">Last name:</label> <input type="text" name="lastname" /><br /> <label for="email">What is your email address?</label> <input type="text" name="email" /> Required<br /> <label for="like">Do you like my website, if no please tell me why?</label>
Yes <input name="like" type="radio" value="does" /> No <input name="like" type="radio" value="does not" /><br /> <label for="message">Your Feed Back</label> <textarea rows="8" cols="40" wrap="virtual" name="message"></textarea><br /> <input type="submit" value="Submit Feedback" name="submit" /> </form> <br /> <?php $first_name = $_POST['firstname']; $last_name = $_POST['lastname']; $email = $_POST['email']; $like = $_POST['like']; $message = $_POST['message']; $dbc = mysqli_connect('172.23.50.3', 'username', 'password', 'website') or die('Error connecting to MySQL server.'); if (!empty($email)) { $query = "INSERT INTO feedback (first_name, last_name, email, `like`, message) " . "VALUES ('$first_name', '$last_name', '$email', '$like', '$message')"; $result = mysqli_query($dbc, $query) or die('Error querying database.');}else { } // Retrieve data base $query = "SELECT * FROM feedback" ; $data = mysqli_query($dbc, $query); // Loop through the array of payment data while ($row = mysqli_fetch_array($data)) { // Display the payment data echo '<strong>' .$row['last_name'] . ' ' . $row['first_name'] . '</strong><br />' ; echo 'This person ' . $row['like'] . ' like this site. <br />'; echo '<strong>What this person had to say:</strong>' . '<br />'; echo $row['message'] . '<br />'; echo '<br />' ;} mysqli_close($dbc); ?> </td></tr> <tr> <td colspan="2" height="280"valign="top"><p align="center"> <?php include "data/footer.php";?> </td> </tr></table></body></html>
Thanks
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this is the errorWarning: mysql_close(): supplied argument is not a valid MySQL-Link resource in /var/www/IpSearch.php on line Code: [Select]<?php$srch = $_REQUEST["srch"];if