I have 3 small testing tables:
ID TYPE
1 pepperoni
2 C. bacon
3 taco
ID TYPE
1 small
2 med
3 large
ID TYPE
1 bud
2 hef
3 mil best
4 7up
5 orange
6 coke
Each one is a select menu. How would I pass these as variables
to the MySql database with one submit button?
I could order a small pepperoni and a coke, or a large pepperoni and a coke or a bud.
How do I handle all these possibilities 1) on the php end and 2) in the sql statement?
This is part of something I have done before from just one table:
Code: $UserArr = chk_lgn($_POST['logname'],$_POST['passwd']);
$sql = "SELECT UserId ,logname FROM tblPass WHERE logname = '$lname' AND passwd = '$pass' ";
These are just general questions of concept/how to proceed. I have tried to make my question
as clear as I can, I hope I succeeded.
Thanks AL123
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Hi Experts,
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hello i'm amir
Is there a more efficient way to code this than what I have?
I have three associative arrays. $combinedSettings$userSettings$defaultSettingsMy function must combine the key and value from $userSettings and $defaultSettings into the $combinedSettings array.
