I probably have this setup wrong well I know I do because nothing is showing up now. What I want is for it to show all the character names that are assigned to each user so yes than can be more than one. Can't figure out where at in my coding is my problem.
table efed_bio
id
charactername
table handler_characters
id
handler_id
bio_id
table efed_handler
id
default_character_id
login
forum_id
Code: <?php {
$query = "SELECT h.login, h.forumname,
bio.charactername AS charactername
FROM efed_bio AS bio, efed_handler_characters AS ech, efed_handler AS h
WHERE h.default_char_id = bio.id
AND ech.handler_id=h.id
AND ech.bio_id=bio.id";
$result = mysql_query ( $query ); // Run The Query
if ($result) {
print '<h1 class=backstage>Active Handler Directory</h1><br />';
print '<table width="100%" class="table1">';
print '<tr class="rowheading">';
print '<td>Name</td>';
print '<td>Forum Name</td>';
print '<td>Characters</td>';
print '</tr>';
// Fetch and print all records.
$i = 0;
while ( $row = mysql_fetch_array ( $result, MYSQL_ASSOC ) ) {
$sClass = 'row2';
if ($i ++ & 1) {
$sClass = 'row1';
}
printf ( "<tr class="%s">", $sClass );
printf ( "<td valign="top">%s</td>", $row [login] );
printf ( "<td valign="top">%s</td>", $row [forumname] );
printf ( "<td valign="top"><ul class="characters"><li>%s</li>", $row [charactername] );
print '</ul></td>';
print '</tr>';
}
print '</table><br />';
print '<h2 class=backstage><form method=POST><input type=hidden name=action value=mainmenu><input type=submit value="Return to Main Menu" class=button200></form></h2>';
}
}
?>
$_POST variable un-useable
I'm trying to use a $_POST variable in a mysql update statement but i can't use it for some unknown reason i can echo the variable and it outputs the correct value but i cannot use that variable in
C++ Http request?
Code:
firefox wouldnt stream mp3 files completely from my php page
hi everyone,I have a php file trying to read and stream mp3 files. It works fine in IE but my problem is Firefox streams only 3 seconds of them.$direction =
Probably a simple error...
I'm getting the error -- Parse error: syntax error, unexpected '{' in /home/content/c/s/t/csteffen242/html/staples/event.php on line 46I checked it over and couldn't find anything wrong with an extra
shift numbers with paging
HiHow would i be able to display 10 numbers 1 2 3 4 5 6 7 8 9 10 and when I click next then 2 3 4 5 6 7 8 9 10 11 and click next then 3 4 5 6 7 8 9 10 11 12are displayed.i am using a for loop to echo
Save User Inputs while javascript reloading!
hi..i have written a PHP code in which i reload the page when user selects a value in dropdown...Code: function reload(form){var
building a function with multiple outputs
I want to build a function that has multiple outputs.I know but am not to sure how I should go about that, the only thing I know won't work is return a;return b;return c; that will return one result
Anti Spam Code Problems
Ok where do i start? Probably by telling you I have very little working knowledge of PHP and that I have been working on this problem for 3 days and have had no luck!Here we go:I have a rate and
problems with search form numerical "between" sending by php
I am trying to display the results of a search, on a sql database, on a web page. I set up html "select form" and set value to "Between x and x" I get a resource error when
Pspell with my own dictionary
Hello!I've tested two cases using pspell functions.1)Code: $dictionary_link = pspell_new_personal ("/.../MyDict","es", "", "", "",