hi i have created a dynamic select menu using php. i have a problem in that which is when the user select any value in that menu and press submit then it does not pass to next page.
my code is here
Code: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Untitled Document</title>
</head>
<body>
<?php
$db = mysql_connect("localhost");
mysql_select_db("test", $db);
$query = "SELECT * FROM day" or die(mysql_error()); // id='".$id."'
//echo $query;
$result = mysql_query($query) or die(mysql_error());
?>
<form name="form1" method="post" action="date.php">
<label>Date:
<select name="day" id="day">
<?php while( $row = mysql_fetch_array($result) ) { ?>
<option value="<?php $row['id']; ?>"><?php echo $row['day']; ?></option>
<?php } ?>
</select>
</label>
<p>
<label>
<input type="submit" name="button" id="button" value="Submit">
</label>
</p>
</form>
</body>
</html>
the next page is
Code: <?php
$day = $_POST["day"];
echo $day;
?>
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what is wrong with this code ? <html><body><?php$conn=odbc_connect('Towel','','');if (!$conn) {exit("Connection Failed: " . $conn);}$sql="SELECT *
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