I have a MySQL db with all my servers and all their details like server name, IP, OS, RAM etc etc 26 in total. I have a PHP page which will list all server names with a link on the page and when you click the link its suppose to go to a page that is called serverdetails.php which it does, but how do I only list information from the one server of the link I clicked on? Below is the code I am using to go to the next page.
echo "<A HREF="http://vm-webdev/serverdetails?svr={$row['Server_Name']}">{$row['Server_Name']}</A>
";
Parse Error Help
Hello, I got the parse error "Parse error: syntax error, unexpected ',' in register.php on line 21Heres the code:Code: <body
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Code error with Index.php
Error: Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /home/runevid/public_html/index.php on line 25<html><head><title>CrazyQuest -
Saas with SAP R/3
hi experts,
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Ey all, my first post here, i hope its not a hard one I display mysql results in a tableEach row has a link which must send the title of the row to "result.php"
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