Okay so I have several "articles" stored in a mysql database and am attempting to echo those onto a PHP page.
so on index.php I have
Code: <?php article_layout();?> (yes there is a require one to get the function but that works)
then page_layout is this
Code: <?php
function article_layout(){
$uri = $_GET['uri'];
if($uri == ""){
$uri = "home";
} else {
$uri = $uri;
};
$mysqli = db_connect();
$qry = "SELECT * FROM `articles` WHERE `uri`='$uri'";
$result = $mysqli->query($qry, MYSQLI_STORE_RESULT);
while ($row = mysqli_fetch_array($result)){
$layout = $row['layout'];
require_once('http://'.$_SERVER['HTTP_HOST'].'/themes/default/layouts/'.$layout.'.php?uri='.$uri.'');
};
};?>
which calls the relevant layout page (so the contents it layed out correctly)
now my problem is how to make this cope with more than one article, so far it is only display one article even if it should be display two. Any ideas?
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