foreach result into a single variable
Hi,I have this code... Code: [Select]foreach ($_POST['Interests'] as $interest => $value) { echo "Interests: $interest; Value: $value";}How do I store the multiple results in a
my two tables
table1 : col1 = topicid , col2 = topictable2 : col1 = sentid, col2 = sentenceCode: require_once("includes/connection.php"); $trends = mysql_query("SELECT topicid, topic FROM
max() problem
I have a while loop to get image names. Code: $imagequery = mysql_query("SELECT * FROM ad_image WHERE user='$user' AND ad='$adnr' ORDER BY `picorder` ASC")or die(mysql_error());$totpics =
Mail Script Problems
I have created a PHP mail script. I am having a problem though. In $body i am trying to put two values side by side like so $Fname $Lname. Where ever i use tag the values appear in the final
True way to see if action was successful?
If this is a good way to see if action was successful to continue:Code: function changeGameState($GameId) { mysql_query("UPDATE challenges SET status=status+1 WHERE id='$GameId'");
* Gridview and Detailsview in UpdatePanel, insert mode problem
I have a GridView and DetailsView working together. When a record from Gridview is selected, DetailsView is opened for edit/insert/deletion of records. When user searches for a record and no record
Images outside webroot
Im hopeing someone can help me with this because i cant figure it out.I have setup an ASP.NET website in C# that allows end users to upload files to the server. I am able to save these files outside
natcasesort works on one server but not on another
HiI have a problem that I was hoping that someone can help me with.I'm trying to use natcasesort() to sort an array. This works fine on my laptop (which I use for testing and which uses php 5.2.6),
Working with popups and such in a class
I've recently started building my applications completely enclosed in classes. I like the fact that I can base everything off one root and work with that, but I'm having a problem with popups
Strange
I recently noticed some odd HTML appear in some of the websites I host. Not all of them are run on a CMS but the majority (but not all) are running through the same FTP account.I've searched
Function
How can I make this function that once you click the link in the code it takes you to a new page without html but so the menu_name and content load in it.Code: function public_navigation($sel_subject
Remove directories not empty
hi,i have an array that contains some names (1,4,6,56...). Every integer is a name of a folder.I must to delete only the folders in array, i use this code:Code: $all_folders = array();while ($row =
Passing JS to PHP
So I have the followingCode: <?phpgetdetails(?><script type="text/javascript">document.write(jsvariable)</script><?php );?>The idea is
how to export excel file in same server
My first post - php newbie, so appreciate your support.I'm currently using headers to save web page as excel file.$filename="sms.xls";header("Pragma: public");header("Expires:
Timer control causing error
I recently decided to add a timer control to an existing page that uses AJAX on my site. As soon as I added the timer control and ran my app, I started getting the following error:Description: An
Pop-up Banner
Hello Friends,I need to use banner in our client site.Example: www.example.com if i enter this site immediately pop-up window should open and the main page at the back should be disabled.If i click
Else statement screws up all css
Does anyone know what goes wrong in the process with this php code?This code seems to be causing it: <?PHP } else { echo " <div
Mysql query, two times?
Hello to all,I'm new to php coding and i like it alot. I need help with some noob stuff.1. Having problem with mysql query after submiting HTML form. It's allways execuding two times, that way i have
Why is the logic of this simple code not working?
Hey, I'm trying to determine if a table already exists in mysql, but doing a query first with mysql_query, then checking $sql as if it a were TRUE of FALSE. Which I though it would be. My Code
Need help with some php code :)
Hey! I'm quite new to this whole thing, so please don't fire me with shait on this one =DI'm trying to learn PHP and MySQL, and atm I am trying to make a website which corresponds with a database - a