Error in query: Resource id #4??

Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out

Your Answer:

Login to answer

Other forums

Receive Rosettanet Message to SAP 4.6c
Dear all ,

My customer will send the PO details by rosettanet message , Is it

Combining refCursors and Summing
Given the following DDL:

CREATE TABLE FOODSALESTEST ("WEEKNBR" NUMBER, "ST

trouble printing an array....
I'm having some trouble printing out an array forwards. I'm figuring out the high and low of an arra

Re-Order by ID Number
I have a cms set up for inputting an image, thumb, title, pdf, and eps. When input the database ass

insert/update functions for mysql, what do you think?
I am working on two really simple functions that automatically generate (and execute) insert and upd

output_buffering so rewrite
I'm planning to rewrite some of my scripts so they don't have to use output buffering to accomplish

Upload Code Help
Hi everyone I need some help with a bit of code ive been working with for a while. I am completely s

Add 5 to a variable when a button is clicked, and re-run a for loop
So I'm making a feedback sort of section on a website with MySQL and PHP, I've gotten the script to

Feed Maker
Hi all.
First of all I must say I am not a php developer so I am afraid I don't know much about i

Problem writing URL into database
How would I write this into the database?

<?php echo "http://".$_SERVER['SER