Error in query: Resource id #4??


Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out

No comments posted yet

Your Answer:

Login to answer
216 Like 41 Dislike
Previous forums Next forums
Other forums

shoping cart issues
i´ve wrote this and works when i add an item to, my cart, but when i want to add othrer item just

Automatically Detect Phone Model for WAP Jar Deployment
Making a wap site is fairly simple, but I'd like to know if there's a way to make it so that the wap

Files in current folder. Should be an easy fix.
Never mind. I've asked about this before and just found my answer. Anyway to delete this?

Why is my row count 0?
Here's the MySQL query i'm running. It basically pulls data from 2 tables based on some data passed.

undefined offset help
Hi All,

I kept getting undefined offset PHP notice for a simple for loop. For eg
$va = arr

How to make URL loads only on login
On my page, when a user login he's redirects to user_home.php. I made it also to open the chat scree

Convert .fdf to .pdf
I currently have a web form that uploads the form data to an .fdf file and emails it.

However

All possible combinations of String in PL/SQL
Hi All,

Could you please explain the logic of getting all possible combinations of String

Oracle11g Patch issue
Hi all,

I'm getting the following error while installing Oracle11g Patch 11.1.0.7.0 on IBM-AI

Module pool selction screen parameters combination logic
Hi floks,
Am new to the module pool development ,Recently i have created one program based on

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash