Error in query: Resource id #4??


Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Did you know?Explore Trending and Topic pages for more stories like this.
Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out
No comments posted yet

Your Answer:

Login to answer
216 Like 41 Dislike
Previous forums Next forums
Other forums

Rand() help needed
Hi all,

Can someone explain and give me a quick example of how I would go about this?

JQuery, Masterpage, and Control issue
Hey everyone, I am using JQuery in several sites so I thought it would be best to place the library

problems with php variables in mysql query
i can't seem to get the following query to work.

select $q1c from $vote_rate where id = $re

echo $rows help
Hi all,

Hopefully something simple that I don't know!

I have this:

Code: [Selec

Internal class functions don't seem to get executed.
Hi. Can someone please put me out of my misery on this. I don't write much PHP and this has me baffl

Company Code for Vendors created through Business Partners
Hi, experts!

I'm trying to set up the integration between Business Partner (BP) and Vendo

IP Logger for Voting Script
Can anybody help me place an IP logger into my voting script?
I know that maybe it is not as secu

Upload Code Help
Hi everyone I need some help with a bit of code ive been working with for a while. I am completely s

how do i display data on a page from mysql
1 - do i use this code at the top of each of my page i wish to only alow access if there as been a s

search function
HI guys,

if anyone could point us in the right direction of how to do this, or provide some t

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash