Error in query: Resource id #4??

Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out

Your Answer:

Login to answer

Other forums

problem with query error
First Thanks to those who helped me on my previous posts, and the following code i'm using is not mi

standard ALV application toolbar, into custom report....
HI,

I have a question regarding displaying standard ALV menu path and application toolbar

Detail Expenses Report by Cost Center
I would like to obtain a report out of SAP that shows a list of expenses by cost center that shows t

LIMIT $start, 10... how to pass last value queried into next page with GET??
Ok I know how to display the first or last 10 results of a query...

$result = mysql_query(&q

url- go to webpage
i have an input text field and submit button.

how do i make the url entered into the textfiel

A little help in c#
i am doing a simple paint program using c# i want to draw with the mouse so i wrote the code of the

Thread in PHP
Thread in PHP
Some basic use and basic code for thread in php
This is my question?

help with email script...
hey

I need help with my mail script

when the form on http://www.mcgdesignstudio.com/c

Drawing Images in classes
I'm quite new to Object Oriented PHP. What I'm trying to do is draw some images but also have other

MSSQL/PHP
I am tryint to setup a webapplication developed in PHP, Apache2.0 and SQLServer2000 as backend which