Error in query: Resource id #4??

Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out

Your Answer:

Login to answer

Other forums

Curl timeout breaks script
So im having difficulties with skipping timeout error in curl
my script calls different functions

image upload script not working with png
The basic process of this php code is to take the submitted file, convert it to a small JPG thumbnai

php/xmlrpc class issue
I am working on xml-rpc in php to start with.

I have a class that only has variables defined

have trouble in a if condition
The if below is working ok, it check when indexes, name, zipcode and state are empty.
Code: &

Comparing two dates
Hi Guys
I have two dates I want to compare. Below is my current implementation. The problem with

$_POST variable un-useable
I'm trying to use a $_POST variable in a mysql update statement but i can't use it for some unknown

Securing a user input - need some confirmation
Hello All,

I am in the process of recoding a large proportion of an e-commerce site, one of t

Remore client postprocessing phase getting dump SAPSQL_ARRAY_INSERT_DUPREC
Hello Expects,I have started remore client copy. Data was copied successfully. but while running pos

help, header() is not working!
Hello, I have this code:


<?php

/**
* @author samoi
* @copyright 200

SELECT * FROM users WHERE Users are not in Blocked
How do I select all users from users table where there users_id is not stored in the block table