Error in query: Resource id #4??
Posted on
16th Feb 2014 07:03 pm by
admin
hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.
my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:
Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);
$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:
here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php
you can login with: username: test password: test
the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=
i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.
if my above code is completely wrong with using the $querystats query, how can i get this to work.
originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.
if you need any more info, please ask, i cant figure this out
No comments posted yet
Your Answer:
Login to answer
216
41
Other forums
* Gridview and Detailsview in UpdatePanel, insert mode problem
I have a GridView and DetailsView working together. When a record from Gridview is selected, Detail
I need help on this PHP code
Hi everybody, I made some kind of mistake while editing the code below. As you see, at the 3 row my
Displaying image pathname instead of image
Hello
Im trying to upload and then display images from a mysql database - Its only basic and
problem with sql querry in php script
Hello guys,
What I want to do is I want to read out a csv file and then but te conent ot the
How would I convert this into code using an if statement?
ES equals exam score m equals $mean s equals $total. I already coded my mean and total so I'm not g
Writing to the middle of a file
Hi I have a bit of a problem. Is there any way i can write some text to a middle of a text file. For
Count of reciepients in php mailer
How can i sent a mail to large no of reciepients say 10,00,00 Using PHP MAILER
If statement help please.
Hello on my site I have 2 content boxes. 1 is for the main content (which is the biggest one) and th
Upload file!
Ok i have a form..
Code: <form name="form1" method="post" action=&quo
Code doesn't print what i wanted it too. Please help!
Hi there,
I wrote this code to mae it so that in the form before it that the user said their