Error in query: Resource id #4??


Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out

No comments posted yet

Your Answer:

Login to answer
216 Like 41 Dislike
Previous forums Next forums
Other forums

PHP Game
hy i was wondering what's the best method in order to make some automatic updates in a php game
<

mysql VARCHAR acting like INT
Hi, All.

I have a table that contains a varchar(10) column named weird_field. In this column

Weird problem with SELECT command..Help!
Hi!

It seems I'm having a really weird problem with SQL SELECT command....I have table into a

Print 'a' to 'z' via for loop
A very simple problem..
How Can I print a to z NOT a to y ?
It is a part of a code where
<

Setting condidtions for an input box
Hi all,

I would like to set a condition in a txt box that says the number a user enters has t

Header is not working in IE
Hi ! header function is not working in IE but it works in FF, Safari, Chrome. any help please. :

Set Categories
I am creating a submission form for somebody to come in and submit products. These products are sep

TimeStamp Column Problem...
I'm mad at my self and thinking I'm a little retarded. It just be some one mistake I'm missing here.

pagination - need help on passing of search query.
Hi, i have been trying for days but couldn't get this sorted out. Would like some professional help

PHP page is blank
Hi Everyone,

I have a site in which I am able to open the first PHP webpage in my browser but

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash