Error in query: Resource id #4??
Posted on
16th Feb 2014 07:03 pm by
admin
hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.
my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:
Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);
$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:
here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php
you can login with: username: test password: test
the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=
i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.
if my above code is completely wrong with using the $querystats query, how can i get this to work.
originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.
if you need any more info, please ask, i cant figure this out
No comments posted yet
Your Answer:
Login to answer
216
41
Other forums
Passing JS to PHP
So I have the following
Code: <?php
getdetails(?><script type="text/
Extracting Long text from message class with parameters
Hi,
I would like to extract the long text from a message class. However, the long text ha
Simple Scraper... Weird Output
Okay, maybe I just need a Blue Monster and some sleep, but....
I'm scraping a ringtone site
Estimations and Effort
HI Gurus,
Would like to know whether SAP have a provision for carrying out the Project es
can i optmize image to 50% quality before uploading 2 server
Hi there
i have jus written a php program to upload and display images but when i try to uplo
if php cookie set, show code...
Hi all.. I need to figure out this little snippet right quick.. seems like it should be easy enough
Download Image from URL and Upload it
Ok, I have been googling for the last 1/2 hour trying to figure this out, Most likely I'm just not s
Calling variables
I want to call this to my website but it doesn't display what I want it to,
Code: <h5&
Match stored value with the current value in a loop
Hello,
I have a MySQL db were I store articles in.
I have a form to fill these article
button.click += new eventhandler() not works in if(!ispostback)
i want to use button.clcik event in function VIewScrap() which is called in if(!ispostback) but itdo