Error in query: Resource id #4??


Posted on 16th Feb 2014 07:03 pm by admin

hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.

my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:

Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);

$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}

while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:



here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php

you can login with: username: test password: test

the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=

i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.

if my above code is completely wrong with using the $querystats query, how can i get this to work.

originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.

if you need any more info, please ask, i cant figure this out

No comments posted yet

Your Answer:

Login to answer
216 Like 41 Dislike
Previous forums Next forums
Other forums

DYNPRO_FIELD_CONVERSION
Hi gurus,

I got a dump when I run one of my program. the dump is described below:

i have no idea why this isn't working
Code: <?php
session_start();
include("connect.php");

error_reporting(E

[function.file]: failed to open stream: No such file or directory
Okay I wrote this little script to upload a csv file that is located on my webhosts server to a mysq

Problem with coding MySQL query
I'm having heaps of trouble getting one of my PHP/MySQL queries to work for some reason (and the fun

Which practice of iteration through containers is preferred
In the "real world" what kind of loop do most people use to iterate through a container like a vecto

listing help
Hi,

at first, great new design!!! I like it,

i got a problem,

I want to list so

limitations on array_unique()
Does any one know what/how imitations are applied to array_unique? I have an issue where no matter h

couldn't connect to your database
Hello I am new to php mysql

Actually i have read A tutorial on nettuts
"http://net.tu

SuperCali PHP Event Calendar
does anyone have any experience with the SuperCali PHP Event Calendar? I could use some assistance

Renaming array keys
The issue: renaming array keys inside a foreach loop.

I'm trying to build a pie chart image w

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash