Error in query: Resource id #4??
Posted on
16th Feb 2014 07:03 pm by
admin
hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.
my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:
Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);
$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:
here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php
you can login with: username: test password: test
the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=
i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.
if my above code is completely wrong with using the $querystats query, how can i get this to work.
originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.
if you need any more info, please ask, i cant figure this out
No comments posted yet
Your Answer:
Login to answer
216 41
Other forums
Need help with cin setw
I made a program here is my code:
#include
#include
#i
Insert numbers from Barcode scanner into online php page
I have a real big problem, Here is what I'm trying to do. I have a Intermec CN3 handheld computer th
need to apply an if/else statement to Tim Thumb script
Not sure how to work this. I essentially want to call a variety of image sizes based on which style
Breaking results into week blocks
I have a set of dates (and times), which are returned from a mySQL query.
These usually span
question about stripslashes and real_escape_string
im cleaning up an old app that I wrote fixing some of the vulernabilities from attacks.
I hav
modifying query string with no page refresh
Hi everybody,
I've tried to get info about my problem all over the internet but i didn't find out
Php Mysql Page Loading Notice
Hi all,
I was wondering if there is a way (Sure there is) of showing a message or an image wh
selection tool on raster image
Hi!
I have to implement in my app a selection tool which lets users to select region of any shape
Join Query Help
Hi all,
I am having problems with the below code, which we shall call 'my first join query'!
Sending CC Info by email
I am a little bit less knowledgable in the security area as most developers and I know I have a lot