Error in query: Resource id #4??
Posted on
16th Feb 2014 07:03 pm by
admin
hey guys, having a minor (i think) problem here that i havent been able to figure out. long story short, im building a hockey stat tracking site for a local hockey league around here.
my problem is, i am trying to run a query using php, but the value getting returned is Resource id #4 instead of what it is supposed to be. i read around and found people saying you need to use mysql_fetch_array, which is what i am doing. let me start by posting my code:
Code: <?php
$querystats = mysql_query('SELECT * FROM stats ORDER BY team_id');
$statsresult = mysql_query($querystats);
if (!$statsresult) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while($row = mysql_fetch_array($statsresult)) {
echo $row['team_id'];
print_r($team_id);
$querystandings = mysql_query('SELECT * FROM standings ORDER BY points DESC');
if (!$querystandings) {
exit ('<p>Error in query.'. mysql_error().'</p>');
}
while ($row = mysql_fetch_array($querystandings)) {
echo('<tr><td>' . '<a href="teams.php?team_id='.$row['team_id'].'"> ' . $row['team'] . '</a></td><td>' . $row['games_played'] . '</td><td>' . $row['wins'] . '</td><td>' . $row['losses'] . '</td><td>' . $row['ties'] . '</td><td>' . $row['points'] . '</td></tr>');
}
}
?>
i believe the problem is the $querystats. here's what my table structure looks like:
here's a link to my site:
http://gamera.caset.buffalo.edu/~sstoveld/DMS315/projects/final/standings.php
you can login with: username: test password: test
the problem is on the standings page, if you hover over a team name and look at where the link directs to, it ends with team_id=
i need to get the proper team_id in the link, which is where im hoping someone can help me. ive been looking through this trying many different things that i cant seem to get to work.
if my above code is completely wrong with using the $querystats query, how can i get this to work.
originally the $querystats query wasnt there, and only the $querystandings query was being used, but the links wouldnt work because i am not selecting the team_id from the stats table. when i modify the $querystandings query to left join on stats, the loop goes through and adds about 25 entries per team, which is not what i want.
if you need any more info, please ask, i cant figure this out
No comments posted yet
Your Answer:
Login to answer
216
41
Other forums
ldap connection
We are using ldap to get user information from the domain controller. It was working before. Recentl
login from external site
Hi my new experience begins, Now what i am trying to do is i make three pages, login.php logout.php
need help modifying script
Hi guys,
I'm fairly new to php and am having a bit of trouble modifying a script.
This
Solution to the FindControl problem
I have seen may posts about having problems with the FindControl method. Most seem to come about bec
Shuffle Array
Hi,
I am writing a script for a game that needs players to randomly be assigned a target (ano
help with mysql_error()
Hi,
I am trying to insert data into a table, but I am not able to insert it. I wanted to see
Hi, explode and strstr.
Hi, I seem to be confused about the strstr function, eg. i have a string like:
"a.b.c.d.e.f&
timezone change with date()
so i put all my times for posts in my made from scratch forum(not phpbb3 or sm)
in my mysql db u
get multiple rows
Hi I want to get multiple rows from a db
I am using this for the db query
Code: public
php code to accept and delete incoming data
Using following HTML Code please show me how to write PHP code to accept and delete the incoming dat