how to use two buttons with php
Posted on
16th Feb 2014 07:03 pm by
admin
hi i have one form. there are three fields which are to be filled by the user. and then there are two buttons. ob clicking first button i want to save user's provided data to the database display the same page again. and on clicking second button the provided data will be saved and will be taken to next page.
my problem is with these buttons how can i set up these buttons to do the the action?
Did you know?Explore Trending and Topic pages for more stories like this.
my code is here
Code: [Select]<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Untitled Document</title>
</head>
<body>
<form name="form1" method="post" action="">
<label>Degree Name:
<input type="text" name="textfield" id="textfield">
</label>
<p>
<label>CGPA:
<input type="text" name="textfield2" id="textfield2">
</label>
</p>
<p>
<label>Institute:
<input type="text" name="textfield3" id="textfield3">
</label>
</p>
<p>
<label>
<input type="submit" name="button" id="button" value="Save And Add Another">
</label>
</p>
<p>
<label>
<input type="submit" name="button2" id="button2" value="Save And Proceed to Next Step">
</label>
</p>
</form>
<?php
$db = mysql_connect("localhost");
mysql_select_db("job", $db);
$addcv = mysql_query("insert into cv
(
degree,
cgpa,
institute
)
values
(
'".$degree."',
'".$cgpa."',
'".$institute."',
)");
echo "Your data is added.";
?>
</body>
</html>
tag inside php... hi
Code: <?php echo "<td width="$columnWidth%" align=&Display a default image
I am trying to display generic image for items that don't have one, but I can't get it to display. Change image filetype on upload? Hi, I've got a form which uploads an image to the server. Is it possible to change the image t Adding Different Numbers From MySQL Basically I have a mysql database with a couple prices as the following:
9.99 9.99 9.99 PHP onsubmit in the form not going to the fuction. I have a form through ‘onsubmit’ calling a function validation(). But not going to the CHECK A STRING FOR ' " ' (DOUBLE QUOTES) I am checking for delimiter (.!?) and if there is a " after a sentence then it should neglect a Strange Oracle Query problem Ok So I have this PHP class that talks to a Javascript class that basically creates a table of infor LOOPing Problem Hello All!
The following code loops through the data and displays the data accordingly. My p
|