need help about


Posted on 16th Feb 2014 07:03 pm by admin

i store the value of my select statement result to an array and stored it to a variable named $fname the i used it as the value of:

<input type='text' name='fname' value=<?php echo $fname ?> />

but when $fname's value is more than 1 word it only displays the first word, but when i:

echo $fname;

i get the right result. What is the problem with this?

Need help. ASAP.

Thanks

No comments posted yet

Your Answer:

Login to answer
85 Like 7 Dislike
Previous forums Next forums
Other forums

PHP webpage & array print issue
I have this code running, and it works perfectly … however, see my bottom bit about what I see

Is it possible to view php source code??
Hi All

I was just wondering if it's possible to view a websites php source code?
I know

Socket Server Response Headers
Earlier I had a post about my Socket Server, I wasn't able to get it to connect, now I can

I

Share admin accross websites
I'm using .net memberships and roles in one of my sites, but I need to be able to share logins and p

Check something, wait, check again, do something!
Hi guys.

I wonder if someone can help me with this.

Basically, what I want to do is (

Not "Just Another" MMORPG - text based.
Hello,

I've been learning MySQL and PHP for the last 2-3 years.
Though, I've had long paus

Matchcode in ALV change header column
Hello everyone,

I am working in an SAP system that is currently in upgrade and conversion

getting most records by count
Code: [Select]<?php

$connect = mysql_connect("localhost","dam

why is it over writing
Code: $filepaths[] = $_FILES['new_image'];
foreach ($filepaths as $filepath)
{
$imagename =

I face problems to extract data from one table and insert it in another one
Hi,

For modifications, I have to extract data from one table and insert it in another one

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash