pagination - need help on passing of search query.


Posted on 16th Feb 2014 07:03 pm by admin

Hi, i have been trying for days but couldn't get this sorted out. Would like some professional help here.
Basically I got a basic pagination script from google search and the script works absolutely well if i am to display the full results.
However i am using the 'SELECT...WHERE.. LIKE %$val%' and the result works well for the 1st page but not on the 2nd or 3rd page. i had a search form to submit my value. Some help as to where i should proceed is greatly appreciated! Cheers
Here's my coding:
Did you know?Explore Trending and Topic pages for more stories like this.

form.php
Code: <form action="FTsearch.php" method="post">
<table border=0 cellspace=1 cellpadding=3 bgcolor;"#353535"
align="center">
<tr>
<td bgcolor="#eeeeff" width="50%">
Device Number
</td>
<td bgcolor="#eeeeff" width="50%">
<INPUT type = "TEXT" name = "devicesearch">
</td>
</tr>
<tr>
<td bgcolor ="eeeeff" colspan=2 align="center">
<INPUT Type="SUBMIT" name="submit" value="Device Search">
</td>
</tr>
</table>
</form>
FTsearch.php
Code: $val_d = $_POST['devicesearch'];

if ($_POST['SEARCH'] = 'Device Search')
{
$sql = "SELECT *
FROM device
WHERE device_num LIKE '%$val_d%' or '%$val_d'";

$results1 = mysql_query($sql) or die ("Sorry no match found!".mysql_error());

//This checks to see if there is a page number. If not, it will set it to page 1
if (!(isset($pagenum)))
{
$pagenum = 1;
}
$pagenum = $_GET['pagenum'];
echo "<center>";


/* if(!isset($_GET['page'])) {
$pagenum = 1;
} else {
$pagenum = $_GET['page'];
} */

$numrows = mysql_num_rows($results1);
$page_rows = 10; //This is the number of results displayed per page
$last = ceil($numrows/$page_rows); //This tells us the page number of our last page

if ($pagenum < 1) //this makes sure the page number isn't below one, or more than our maximum pages
{
$pagenum = 1;
}
elseif ($pagenum > $last)
{
$pagenum = $last;
}

$max = 'limit ' .($pagenum - 1) * $page_rows .',' .$page_rows; //This sets the range to display in our query

$sql = "SELECT *
FROM device
WHERE device_num LIKE '%$val_d%' or '%$val_d' $max";
$results = mysql_query($sql) or die (mysql_error());

// this is the result display
include "FTsearchtable.php";


echo "

<center>Page $pagenum of $last

"; // This shows the user what page they are on, and the total number of pages

// First we check if we are on page one.
//If we are then we don't need a link to the previous page or the first page so we do nothing.
//If we aren't then we generate links to the first page, and to the previous page.
if($pagenum>1)
{

echo " <a href='{$_SERVER['PHP_SELF']}?&pagenum=1'>First</a> ";
$previous = $pagenum-1;
echo " <a href='{$_SERVER['PHP_SELF']}?&pagenum=$previous'>Previous</a> ";
}
//This does the same as above, only checking if we are on the last page, and then generating the Next and Last links
if ($pagenum == $last)
{
}
else
{
$next = $pagenum+1;
echo " <a href='{$_SERVER['PHP_SELF']}?&pagenum=$next'>Next</a> ";
echo " ";
echo " <a href='{$_SERVER['PHP_SELF']}?&pagenum=$last'>Last</a> ";
}

}
No comments posted yet

Your Answer:

Login to answer
265 Like 38 Dislike
Previous forums Next forums
Other forums

Form Help
Here is the form:

Line number On/Off | Expand/Contract<? include("../include/sess

Creating a unique 'control panel' for each user
Hi there,

I'm thinking of designing a site that will allow users to sign up and have their ow

Read from forum
Haven't written anything forever and I would like to get back.
What I'm trying to do is getting t

Problem with umlauts and UTF-8
Hello every1,

I'm creating my own little CMS at the moment and got some problems with the cha

PL/SQL: ORA-00947: not enough values error message
Hi all i am getting Error(25,63): PL/SQL: ORA-00947: not enough values error message when executing

PHP & Images [Resize, Crop, Save]
Hey! Well I have a little dilema, hoping I could find some guidance.

I have a CMS and on the

Help on Order Entry Form/System Where is best to begin.
I have a dilema and a very short amount of time at this point and I'm looking for some help on decid

FROM_UNIXTIME($phpdate);
Hello,

I tried to use this :

$date = FROM_UNIXTIME($phpdate);

ANd I was t

Grouping and sorting results
Please help with this query.

I have 2 tables in a database, countires and cities. states look

InternetOpenUrl() Invalid cert
Hi all,

Does anyone know how to prevent calls to InternetOpenUrl() from failing with erro

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash