PHP Search Issue

Posted on 16th Feb 2014 07:03 pm by admin

Hi, I am using the following code to search and return flights from a database. The user searches by inputting a DepID and an ArrID and I want to display only flights that match both DepID and ArrID. However at the moment I am get results only from DepID.. Im sure its something simple but any help appreciated.

Code: <?php
if(isset($_POST['submit'])){
if(isset($_GET['go'])){
if(preg_match("/^[ a-zA-Z]+/", $_POST['DepID'], $_POST['ArrID'])){
$DepID=$_POST['DepID'];
$ArrID=$_POST['ArrID'];
//connect to the database
$db=mysql_connect ("localhost", "HIDDEN", "HIDDEN") or die ('I cannot connect to the database because: ' . mysql_error());
//-select the database to use
$mydb=mysql_select_db("HIDDEN");
//-query the database table
$sql="SELECT FlightNo, DepID, DepTime, ArrID, ArrTime, Equip FROM routes WHERE DepID LIKE '%" . $DepID . "%' OR ArrID LIKE '%" . $ArrID ."%'";
//-run the query against the mysql query function
$result=mysql_query($sql);
//-create while loop and loop through result set
while($row=mysql_fetch_array($result)){
$FlightNo=$row['FlightNo'];
$DepID=$row['DepID'];
$DepTime=$row['DepTime'];
$ArrID=$row['ArrID'];
$ArrTime=$row['ArrTime'];
$Equip=$row['Equip'];

//-display the result of the array
echo "<ul>n";
echo "<li>" .$FlightNo . " " . $DepID . " " . $DepTime . " " . $ArrID . " " . $ArrTime . " " . $Equip . "</a></li>n";
echo "</ul>";
}
}
else{
echo "<p>Please enter a search query</p>";
}
}
}
?>

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