Unable to display contents in Second Drop Down Box
Posted on
16th Feb 2014 07:03 pm by
admin
Hi All,
What I am trying to do is 2 dependent drop down boxes and when user selects submit button the values are to be passed to the database to run a insert query.
Right now, I am stuck with the second drop down box because it does not show up the values based on the selection in the first drop down box.
Important point here is " My second drop down box displays columns from a single row(returned from second query)"
Attached is my code please do suggest me the required changes to make and also I pasted the code here,
<?php
include("../include/dbcommon.php");
if(isset($_GET["country"]) && is_numeric($_GET["country"]))
{
$country = $_GET["country"];
$emp_number=$country;
echo($emp_number);
}
if(isset($_GET["state"]) && is_numeric($_GET["state"]))
{
$state = $_GET["state"];
$emp_positionheld=$state;
echo ($emp_positionheld);
}
?>
<script language="JavaScript">
function autoSubmit()
{
var formObject = document.forms['theForm'];
formObject.submit();
}
</script>
<form name="theForm" method="get">
<select name="country" onChange="autoSubmit();">
<option value="null"></option>
<?php
//POPULATE DROP DOWN MENU WITH Employee Names
$sql = "SELECT EmployeeNumber,LastName FROM employees";
$countries = mysql_query($sql,$conn);
while($row = mysql_fetch_array($countries))
{
echo ("<option value="$row[EmployeeNumber]" " . ($country == $row["EmployeeNumber"] ? " selected" : "") . ">$row[LastName]</option>");
}
?>
</select>
<?php
if($country != null && is_numeric($country) )
{
?>
<select name="state" onChange="autoSubmit();">
<option value="null"></option>
<?php
//POPULATE DROP DOWN MENU WITH Job Position helds For a Given Employee
$sql = "SELECT * FROM employee_positionheld WHERE EmployeeNumber = $country ";
$states = mysql_query($sql);
$row = mysql_fetch_array($states);
for($k=1;$k<=6;$k++)
{
echo("inside for");
$temp[$k]='Position held' . ' '.$k;
$queryvar=$temp[$k];
//echo($queryvar);
echo ("<option value="$row[$queryvar]" " . ($state == $row[$queryvar] ? " selected" : "") . ">$row[$queryvar]</option>");
}
?>
</select>
<?php
}
?>
</form>
MY EMPLOYEE_POSITION HELD TABLE looks like this
EmployeeNumber Employee Name Position held 1 Position held 2 Position held 3 Position held 4 Position held 5 Position held 6
34550 Suraj Entryleveltech1 Seniortech1 programmer1 0 0 0 0
No comments posted yet
Your Answer:
Login to answer
272
26
Other forums
Log $_POST
How would i log submits on a form, by everyone? I want to then echo the number of submissions.
pass form variables straight to email, no database required?
hello all,
im working on this form...
http://www.adobedayevents.com/project_request/pr
Multiple arrays inside data
Hi,
Simple question. I have a column called "array" in my database, and inserted in
Why is my row count 0?
Here's the MySQL query i'm running. It basically pulls data from 2 tables based on some data passed.
Echo multiple lines of html code
Hi guys,
I would like to know if there is a way to echo multiple lines of html codes.
Auto-populating dropdowns and multiple forms.
Here's what I have so far:
First drop down = select a state (works)
This populates the sec
mysql VARCHAR acting like INT
Hi, All.
I have a table that contains a varchar(10) column named weird_field. In this column
Getting Subdomain Name With PHP?
I want to grab the subdomain name with PHP so I can generate database queries.
for example my
updating a single value to multiple non consecutive rows
I need to update the same value to multiple non consecutive rows. I need to add an experation date t
Setting a default timezone?
I have read about how to change the timezone in PHPMYADMIN, but it changes back, it doesn't STAY the