Unable to display contents in Second Drop Down Box


Posted on 16th Feb 2014 07:03 pm by admin

Hi All,

What I am trying to do is 2 dependent drop down boxes and when user selects submit button the values are to be passed to the database to run a insert query.

Did you know?Explore Trending and Topic pages for more stories like this.
Right now, I am stuck with the second drop down box because it does not show up the values based on the selection in the first drop down box.

Important point here is " My second drop down box displays columns from a single row(returned from second query)"

Attached is my code please do suggest me the required changes to make and also I pasted the code here,


<?php
include("../include/dbcommon.php");

if(isset($_GET["country"]) && is_numeric($_GET["country"]))
{
$country = $_GET["country"];
$emp_number=$country;
echo($emp_number);
}
if(isset($_GET["state"]) && is_numeric($_GET["state"]))
{
$state = $_GET["state"];
$emp_positionheld=$state;
echo ($emp_positionheld);
}
?>

<script language="JavaScript">
function autoSubmit()
{
var formObject = document.forms['theForm'];
formObject.submit();
}
</script>
<form name="theForm" method="get">
<select name="country" onChange="autoSubmit();">
<option value="null"></option>
<?php
//POPULATE DROP DOWN MENU WITH Employee Names
$sql = "SELECT EmployeeNumber,LastName FROM employees";
$countries = mysql_query($sql,$conn);
while($row = mysql_fetch_array($countries))
{
echo ("<option value="$row[EmployeeNumber]" " . ($country == $row["EmployeeNumber"] ? " selected" : "") . ">$row[LastName]</option>");
}
?>
</select>



<?php
if($country != null && is_numeric($country) )
{
?>
<select name="state" onChange="autoSubmit();">
<option value="null"></option>
<?php
//POPULATE DROP DOWN MENU WITH Job Position helds For a Given Employee
$sql = "SELECT * FROM employee_positionheld WHERE EmployeeNumber = $country ";
$states = mysql_query($sql);
$row = mysql_fetch_array($states);
for($k=1;$k<=6;$k++)
{
echo("inside for");
$temp[$k]='Position held' . ' '.$k;
$queryvar=$temp[$k];
//echo($queryvar);
echo ("<option value="$row[$queryvar]" " . ($state == $row[$queryvar] ? " selected" : "") . ">$row[$queryvar]</option>");
}
?>
</select>
<?php
}
?>
</form>

MY EMPLOYEE_POSITION HELD TABLE looks like this

EmployeeNumber Employee Name Position held 1 Position held 2 Position held 3 Position held 4 Position held 5 Position held 6

34550 Suraj Entryleveltech1 Seniortech1 programmer1 0 0 0 0
No comments posted yet

Your Answer:

Login to answer
272 Like 26 Dislike
Previous forums Next forums
Other forums

query based on 2 conditions
I want to select if the doc_type is either s OR f but this doesn't work:

Code: [Select]$query

Ball movement
I want to move a ball from one point to another and it should hit a group of balls at the other end

WELCOME SCREEN
first of all let me tell you what does my script do,

it´s a very simple query to show a e

Date Format
Hi there,

I have a date format like this right now:
Sat, 17 Oct 2009 17:04:00

I ne

Display data returned from Ajaxservices!!
I have a question about displaying results using ajax. I have part of the code below.
$.ajax({

session checking in page load
hai all I have a web site is www.Mryas.com in this my login page is Page1.aspx its co

adding up might be solved tell us cheers.
i think i finally solved this anybody.

last time i was getting the wrong results.

Code

How to schedule the a job?
Hi,
I have prepared a task ( i.e. a procedure is prepare the file and send the same to con

Switch letters in message (basic cryptology)...
I am trying to switch letters around in a message for an application on my site (see here). The prob

I need help on this PHP code
Hi everybody, I made some kind of mistake while editing the code below. As you see, at the 3 row my

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash