Unable to display contents in Second Drop Down Box
Posted on
16th Feb 2014 07:03 pm by
admin
Hi All,
What I am trying to do is 2 dependent drop down boxes and when user selects submit button the values are to be passed to the database to run a insert query.
Right now, I am stuck with the second drop down box because it does not show up the values based on the selection in the first drop down box.
Important point here is " My second drop down box displays columns from a single row(returned from second query)"
Attached is my code please do suggest me the required changes to make and also I pasted the code here,
<?php
include("../include/dbcommon.php");
if(isset($_GET["country"]) && is_numeric($_GET["country"]))
{
$country = $_GET["country"];
$emp_number=$country;
echo($emp_number);
}
if(isset($_GET["state"]) && is_numeric($_GET["state"]))
{
$state = $_GET["state"];
$emp_positionheld=$state;
echo ($emp_positionheld);
}
?>
<script language="JavaScript">
function autoSubmit()
{
var formObject = document.forms['theForm'];
formObject.submit();
}
</script>
<form name="theForm" method="get">
<select name="country" onChange="autoSubmit();">
<option value="null"></option>
<?php
//POPULATE DROP DOWN MENU WITH Employee Names
$sql = "SELECT EmployeeNumber,LastName FROM employees";
$countries = mysql_query($sql,$conn);
while($row = mysql_fetch_array($countries))
{
echo ("<option value="$row[EmployeeNumber]" " . ($country == $row["EmployeeNumber"] ? " selected" : "") . ">$row[LastName]</option>");
}
?>
</select>
<?php
if($country != null && is_numeric($country) )
{
?>
<select name="state" onChange="autoSubmit();">
<option value="null"></option>
<?php
//POPULATE DROP DOWN MENU WITH Job Position helds For a Given Employee
$sql = "SELECT * FROM employee_positionheld WHERE EmployeeNumber = $country ";
$states = mysql_query($sql);
$row = mysql_fetch_array($states);
for($k=1;$k<=6;$k++)
{
echo("inside for");
$temp[$k]='Position held' . ' '.$k;
$queryvar=$temp[$k];
//echo($queryvar);
echo ("<option value="$row[$queryvar]" " . ($state == $row[$queryvar] ? " selected" : "") . ">$row[$queryvar]</option>");
}
?>
</select>
<?php
}
?>
</form>
MY EMPLOYEE_POSITION HELD TABLE looks like this
EmployeeNumber Employee Name Position held 1 Position held 2 Position held 3 Position held 4 Position held 5 Position held 6
34550 Suraj Entryleveltech1 Seniortech1 programmer1 0 0 0 0
No comments posted yet
Your Answer:
Login to answer
272
26
Other forums
Problem with Subscreen
Dear Experts ,
I am facing a problem with the subscreens. My senario is as follows :
Retail terminologys not been altered after activing Retail System
Hi, All
After I active Retail System via TCode SWF5, the terms does not been changed, th
why preg_match_all does not return the number of matches
My regex looks like
X[^x{4e00}-x{9fa5}]*Y
(where X and Y are two Chinese characters)
I think i'm using the syntax incorrectly
Hi Everyone!
I'm new to this forum and a newbie with PHP - I'm glad I found this site - I hop
reading xml faster than DB call?
I am trying to optimize a high traffic website, and I enabled a feature where there are three photos
Problem in back link
I have page where i have given javascript back link but when i click on it browser give a message
DOMDocument
Hello All,
I need to take an XML document, modify some of the nodes in it and then perform a
Recode Abap Dynpro into Web Dynpro
Hi All,
A client has asked us to look at rearchitecting a custom transaction that was developed
RSS feed - FeedList for WordPress
Hi,
I'm trying to alter the FeedList plugin for WordPress so that I can click on the title of
$_GET problem
Hi all,
Have a bit of a problem with a little piece of code, I am not sure if this should be