Using two $_POST Function / Switch () statements, second does not work.


Posted on 16th Feb 2014 07:03 pm by admin

Hi all. I’m new to php and am having a problem getting $_POST Function / switch () to work. I am coding a registration form. I ask the user a Yes/No question. Depending on the answer I have an Include () bring in the coding for the next step of the registration process, which also has a Yes/No question. I am using submit buttons for the user to give me the answers.

The first $_POST Function / switch () works and will include () the proper coding. The second $_POST Function / switch () does not work.

Both are essentially the same coding with just the variable name changed.

This is the coding used:

<form action="register.php" method="post" name="regForm" id="regForm">
//
HTML in between, input user first name / last name
//
(This works)

// Asking if user is a real estate agent

<?php

$agent = " ";

if (!isset($_POST['agent']))
{
//If not isset -> set with dummy value
$_POST['agent'] = " ";
}

?>

<table align = "center" border="5" cellpadding="3" cellspacing="0">

<col width="430" >

<tr align = "center">

<td>

Are you a licensed Florida real estate agent?



// This is the submit buttons

<input type="submit" name="agent" value="No">&nbsp;&nbsp;

<input type="submit" name="agent" value="Yes">

</td>

</tr>

</table>

// Yes / No switch

<?php

$agent = $_POST['agent'];

switch( $agent ) {
case 'No':
include ("register_3.php");
break;
case 'Yes':
include ("register_2.php");
break;
}

?>

Once the above Yes/No is executed it brings in:

(This does not work)

// Asking if user want to sign up for foreclosure list

<?php

$forlst = " ";

if (!isset($_POST['forlst']))
{
//If not isset -> set with dummy value
$_POST['forlst'] = " ";
}

?>
<table align = "center" border="5" cellpadding="3" cellspacing="0">

<col width="430" >

<tr align = "center">

<td>

Would you like to receive our weekly foreclosure list (by email)



//This is the submit buttons

<input type="submit" name="forlst" value="No">&nbsp;&nbsp;

<input type="submit" name="forlst" value="Yes">

</td>

</tr>

</table>

// Yes / No switch

<?php

$forlst = $_POST['forlst'];

switch( $forlst ) {
case 'No':
include ("register_4.php");
break;
case 'Yes':
include ("register_4.php");
break;
}

?>

What am I doing wrong? Do I need to some how clear the POST before I use the function again? If so, how do I do it?

No comments posted yet

Your Answer:

Login to answer
103 Like 46 Dislike
Previous forums Next forums
Other forums

void* and sizeof()
Hi,

Using void* and sizeof is it possible to get the value of the object ?

I understan

Help on code output
My CODE:

Code: [Select] echo "<phone>".$line["phone"].&qu

How to show more than 1 users with this code...
Hello,
i have a table that shows users only if I, as Administrator, want to be shown. But its sho

Unidentified index error in a simple form
I have been trying to make an HTML form that is handled by a PHP script. So far my attempts to get i

How to get variable value on next page
Hello friends
i am working on payentry page ..there i have this code.........

PHP code needed to get/post form fields and request mysql query results.
I'm new to PHP

I've created an html form to allow the user to request a basic telephone dire

array_combine() error
getting an "Warning: array_combine() [function.array-combine]: Both parameters should have an e

Need Successful Return
Hello I am currently working a form here, and I have everything figured out except when I click the

same querie, or a new one??
Hi guys,

I'm still working on this drop down list. I've got the actual drop down list to wor

Fatal error: Call to a member function fetchrow() on a non-object in C:xamppht
okay i have this query and everytime i add `item_id`=? to it... it gives me the error in the title..

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash