newbie question about multiple queries
Posted on
16th Feb 2014 07:03 pm by
admin
hi everyone,
I'm sorry to ask such a basic question, but I'm young and trying to learn php on my own. I bought the PHP6 Bible and I'm doing a tutorial on multiple-queries.
I followed the book exactly, but I'm not getting the right result.
here's my code:
Code: [Select]<?php require_once('Connections/mydb.php'); ?>
<?php
if (!function_exists("GetSQLValueString")) {
function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
{
$theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue;
$theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue);
switch ($theType) {
case "text":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
break;
case "long":
case "int":
$theValue = ($theValue != "") ? intval($theValue) : "NULL";
break;
case "double":
$theValue = ($theValue != "") ? "'" . doubleval($theValue) . "'" : "NULL";
break;
case "date":
$theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL";
break;
case "defined":
$theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue;
break;
}
return $theValue;
}
}
?>
<?php
function display_cities($database_mydb, $mydb)
{
mysql_select_db($database_mydb, $mydb);
$country_query = sprintf("Select 'id', continent, countryname from country order by continent, countryname");
$country_result = mysql_query($country_query, $mydb) or die(mysql_error());
print("<table border=1>n");
print("<tr><th>continent</th><th>country</th><th>cities</th></tr>");
while ($country_row = mysql_fetch_row($country_result))
{
$country_id = $country_row[0];
$continent = $country_row[1];
$country_name = $country_row[2];
print("<tr style='background:red'align=left valign=top>"); print("<td>$continent</td>"); print("<td>$country_name</td>");
print ("<td style='background:blue'>");
$city_query = "select cityname from city where countryID = $country_id order by cityname"; //<----Something with this line is throwing it off!
$city_result = mysql_query($city_query, $mydb) or die(mysql_error());
while ($city_row = mysql_fetch_row($city_result))
{
$city_name = $city_row[0];
print("$city_name
");
}
print("</td></tr>");
}
print("</table>n");
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Untitled Document</title>
</head>
<body>
<?php
display_cities($database_mydb, $mydb)
?>
</body>
</html>
I've narrowed my problem down to this line "$city_query = "select cityname from city where countryID = $country_id order by cityname";" but that's how the book shows it. But, when I change that line of code to something like "$city_query = "select cityname from city where countryID = 4 order by cityname", then I get all of the cities with a countryID of 4, but they ALL print over and over again in each <td> for the duration of the loop.
I have about 15 entries in the "city" database, and they're all supposed to be echoing into the table, inline with their corresponding country.
This has been driving me nuts for hours, and I've been searching online for an answer. I'm sure I'm overooking something very simple, but please go easy on me, this is my first time attempting this! If someone sees the problem, can you please let me know?
thanks
235 
19 
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