Where am I going wrong


Posted on 16th Feb 2014 07:03 pm by admin

Been trying to work this out for hours

I have two tables called 'Genres' and 'Films'. Genres contains two columns 'Genre_id' and 'Genre_Name'. Films contains a load of columns, the most important being 'Title', 'Year', Director', 'Genres'. Now im trying to create a page where the user can edit a film in the 'Films' table. I want this form to already be populated with the existing values which the user can then delete and enter new ones. Heres the code:

Code:
<?
include 'connect.php';
$FilmID= $_GET['id'];
$result = mysql_query("SELECT Films.*, Genres.Genre_id, Genres.Genre_Name FROM Films INNER JOIN Genres ON Films.Genres = Genres.Genre_id WHERE Films.Film_id = $FilmID" ,$linkme) or die ('Error: '.mysql_error ());

$row = mysql_fetch_array($result);
$current_Genre = $row['Genre_Name'];
$current_Genre_id = $row['Genre_id'];

?>
<form method="post" action="update2.php?id=<? echo $FilmID ?>">
<table>
<tr>
<td>Title</td>
<td><input name = "Title" value="<? echo $row['Title'] ?>" type="text" /></td>
</tr>
<tr>
<td>Year</td>
<td><input name = "Year" value="<? echo $row['Year'] ?>" type="text" /></td>
</tr>
<tr>
<td>Director</td>
<td><input name = "Director" value="<? echo $row['Director'] ?>" type="text" /></td>
</tr>
<tr><td>
Genre:</td><td> <select name="Genre">
<option value = "<?php echo $current_Genre_id ?>"> <? echo $current_Genre ?> </option>
<?
$result = mysql_query("SELECT * FROM Genres",$linkme) or die ('Error: '.mysql_error ());
while($row = mysql_fetch_array($result));
{ ?>
<option value = "<?php echo $row['Genre_id'] ?>"> <? echo $row['Genre_Name'] ?> </option>
<? } ?>
</select></td>
</tr>
</table>
<input name="Update" type="submit" value="Update" />
</form>
<?
include 'close.php';
?>
<a href = "../admin.php">Back</a>


and heres the second page that actually changes the values:

Code:
<?
include 'connect.php';
$Title = $_REQUEST["Title"];
$Year = $_REQUEST["Year"];
$Director = $_REQUEST["Director"];
$Genre = $_REQUEST["Genre"];
$FilmID = $_GET['id'];

$result = mysql_query("UPDATE Films SET Title = '$Title' , Year = '$Year', Director ='$Director', Genre ='$Genre' WHERE Film_id = '$FilmID'",$linkme);
include 'close.php';
?>
Record Updated<br />
<a href = "../admin.php">Back</a>


There are no errors, the values just dont show up in the form, Where am I going wrong??

154 Like 19 Dislike
Previous php-forum Next php-forum
Other php-forum

How to ask a regex question?
Hi, I thought I'd share some of my insight after seeing too many bad questions that either get ignor

Had a simple form script that suddenly stopped working
It was made about a year ago and had been working fine. Last time it was known to work for sure was

Remove letter from numeric textbox
I have a textbox that will search the employee database by entering in the employee ID and it will r

Writting a script to arrange images........ need some help
Ok so here is the link

http://hmtotc.com/dev/projects/vrassociates/jeweler_dev/admin/index.ph

AutoChoosing a CSS file based on URL
Hey everyone,

I have a site that has multiple URLs and CSS files.

Based on the URL tha

Displaying a clickable playername
I am going wrong somewhere with the mysql_query, can someone please put me straight?

$playern

PHP error (line 38) my website
Hello everyone, I'm new on this
and I got a web site thats got a error not showing the photos on<

PHP template help
Ok, I don't know if anyone can help me but I am using PHP templates to make a site. I am a newbie an

PHP form help required
Hi all! Apologies in advance for having to message the forum for help. I know you must get a lot of

PHP File Upload Problem
Hi, I have written a very simple file upload script but it fails for reasons I can't explain. Hope

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash