InternetOpenUrl() Invalid cert


Posted on 16th Feb 2014 07:03 pm by admin

Hi all,

Does anyone know how to prevent calls to InternetOpenUrl() from failing with error 12045 (ERROR_INTERNET_INVALID_CA)? I have the following code below:

Did you know?Explore Trending and Topic pages for more stories like this.
Code: HINTERNET IntOpen = ::InternetOpen(L"Sample", LOCAL_INTERNET_ACCESS, NULL, 0, 0); HINTERNET handle = ::InternetOpenUrl(IntOpen, L"https://192.168.1.10/file.txt", NULL, NULL, INTERNET_FLAG_IGNORE_CERT_CN_INVALID, NULL); if (handle == NULL) { cout << "Error opening URL, " << GetLastError(); return 1; } char buf[1024]; DWORD dwRead = 0; while (InternetReadFile(handle, buf, sizeof(buf), &dwRead) == TRUE) { if (dwRead == 0) break; cout << buf; } This works OK on valid sites, but since my server has a self signed certificate, it fails with error code 12045. I know the INTERNET_FLAG_IGNORE_CERT_CN_INVALID is technically looking for hostname mismatches, and not invalid CA's.

Any help would be appreicated.

Thanks,
No comments posted yet

Your Answer:

Login to answer
270 Like 36 Dislike
Previous forums Next forums
Other forums

Display last record first.
I need some help how put the last record first and first record last.

Thanks

Code: &am

Help With Showing Users On the Index Page
Ive got this code which works just how i want it to.

Code: <?
$timenow=time();

help connecting a form to php and then emailing the form
Ok. So, I made a form, and I need help to where when submitted, I get an email with the submitted de

Checking if field is empty AND using !is_numeric
Hi lads,

Need to be able to display an error message (using isset?) that says "Cant lea

PHP Code reffering to database, doing something wrong.. pls help
Well i am quite new with PHP
and for school we have to make a PHP script which reffers to a Data

mysq_num_rows
Hi,

I want to use:

Code: if(mysql_num_rows($ergebnis2)==2)
how can the value 2, be

$action = "insert"; //$action = $_GET['action'];
$action = "insert";
//$action = $_GET['action'];

why is this invalid type? I am

Gaining access to Drop Down Menu Variable
code is below, I am creating a drop down menu. I want to echo the value selected in the drop down me

Help with looping
I have a comma separated list of colors taken from a database ($ICo) and a directory of images named

Combining Two Queries
I have two scripts that each work fine by themselves. One is a search script with a variable that de

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash