Write Forums

OPINIONS WANTED

Posted on 16th Feb 2014 07:03 pm by admin

This is my login page code, and I want your opinion on it please!

Code: // Login ~ CHECKS THE (USERNAME/PASSWORD) ENTERED BY THE USER THEN EITHER GRANTS ACCESS OR DENIEDS ACCESS
case "Login":
if(!preg_match("/^[a-z0-9]{2,20}$/i", $_POST["F_1_Login_Username"]) || !preg_match("/^[a-z0-9]{2,20}$/i", $_POST["F_1_Login_Password"])){
$Login_Error = "INCORRECT ACCOUNT INFORMATION";
}
if(!$Login_Error){
$Login_Username = $DB->real_escape_string($_POST["F_1_Login_Username"]);
$Login_Password = $DB->real_escape_string(md5($_POST["F_1_Login_Password"]));
$Login_Check = $DB->query("SELECT id,username,account_status,suspended_timestamp FROM members WHERE username='$Login_Username' && password='$Login_Password'");
$Login_Status = $Login_Check->num_rows;
$Login_Information = $Login_Check->fetch_object();
if($Login_Status){
if($Login_Information->account_status == 0){
if(!QUICK_STATUS_CHECK($DB,$Login_Information->id,$TIMESTAMP)){
$_SESSION["USER_ID"] = $Login_Information->id;
$USER_ID = $Login_Information->id;
$DB->query("UPDATE members SET last_action='$TIMESTAMP' WHERE id='$USER_ID'");
}else{
$Login_Error = "YOU ARE CURRENTLY LOGGED IN ALREADY";
}
}elseif($Login_Information->account_status == 1){
if($Login_Information->suspended_timestamp < $TIMESTAMP){
if(!QUICK_STATUS_CHECK($DB,$Login_Information->id,$TIMESTAMP)){
$_SESSION["USER_ID"] = $Login_Information->id;
$USER_ID = $Login_Information->id;
$DB->query("UPDATE members SET account_status='0' WHERE id='$USER_ID'");
$DB->query("UPDATE members SET last_action='$TIMESTAMP' WHERE id='$USER_ID'");
}else{
$Login_Error = "YOU ARE CURRENTLY LOGGED IN ALREADY";
}
}else{
$Login_Error = "ACCOUNT SUSPENDED FOR 24 HOURS";
}
}else{
$Login_Error = "ACCOUNT BANNED";
}
}else{
$Login_Error = "INCORRECT ACCOUNT INFORMATION";
}
}
if($USER_ID){
TEMPLATE(0,0);
SMOOTH_REDIRECT("Redirecting","index.php");
TEMPLATE(1,0);
}else{
LOGIN_FORCE($USER_ID, $Login_Error);
}
break;
The code above works 100%, I just want to see if I missed any security things or programmed it crappy

No comments posted yet

344 5 Tweet

 formating when pulling data from a mysql database 
Ok so Im not to sure if this is the right thread to post in but here is my catch 22 issue.

I 
extending tidy 
I have problem with type-hinting and extending tidy. This code creates error:
Code: class cMyTidy
Add 5 to a variable when a button is clicked, and re-run a for loop 
So I'm making a feedback sort of section on a website with MySQL and PHP, I've gotten the script to 
Web Application Recipe 
Hi Guys!

    I am working with the Web Application recipes. I am currently working on the sen
Greek characters in php 
Hi,

I'm making a script and I m using for first time greek characters.
I started to write