$_GET problem
Posted on
16th Feb 2014 07:03 pm by
admin
Hi all,
Have a bit of a problem with a little piece of code, I am not sure if this should be under php or ajax as I am not sure where the problem lies. Basically here is the script:
Did you know?Explore Trending and Topic pages for more stories like this.
Code: [Select]while($row = mysql_fetch_assoc($query))
{
echo "<center><tr><td style='color:#00F' align='center'>";
echo "<a href='./pages/stockpage.php?id=";
echo $row["stock_id"];
echo "' title='Contact Us' onclick='Modalbox.show(this.href, {title: this.title, width: 600}); return false;'>";
echo $row['stock_name'];
echo "</a></td><td align='center'>";
echo $row['t_val'];
echo "</td><td align='center'>";
echo $row['quant'];
echo "</td><td align='center' style='color:#00F'>";
echo $row['TotValue'];
echo "</td><td>buttonhere</td></tr>";
$TotValue += $row['TotValue'];
}
All this does is display info from the database, the problem I have is with the link. If I put my mouse over the link before clicking I get the correct url, ie http://localhost/stockluck/pages/stockpage.php?id=0.
The link is meant to open in a modalbox ajax popup, this is the code for stockpage is as follows:
Code: [Select]<?php
include('../common/dbconnect.php');
$stock_id = $_GET['stock_id'];
$query="SELECT * FROM stocks WHERE stock_id='$stock_id'"
or die(mysql_error());
while($row = mysql_fetch_assoc($query))
{
echo $row['stock_name'];
}
?>
However, the value for $stock_id is coming back as undefined. Any ideas what is causing this?
Thanks
No comments posted yet
Your Answer:
Login to answer
200
34
Other forums
Need help making login verification cleaner...
I use the below to verify user login. I first check the cookie for the id, ip and a unique id. If it
Seperate team from score
I am writing a site that does a NFL Pick 'em type application and I have a feed that gives me the sc
get font info from a font file
hello,
Does anyone know how to get font info from a font file ... using php of course !
<
Connecion issue
Hi,
For some reason, I keep getting this error when trying to connect:
Warning: mysql_
problems with contact forms that are only protected against SQL injections
What could be a potential problem with contact forms that are only protected against SQL injections
Different actions for different parts of a string
<?php
function dosomething($string, $else = '') {
if (empty($else))
$string
How to show more than 1 users with this code...
Hello,
i have a table that shows users only if I, as Administrator, want to be shown. But its sho
how to remove in php string display
My code is
$message="We're looking at developing our website.";
$body= "My mess
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
what is wrong with this
Code: [Select]<?php
if ($_SERVER['HTTP_REFERER'])
{
pass form variables straight to email, no database required?
hello all,
im working on this form...
http://www.adobedayevents.com/project_request/pr