Quick fix: Conditional statement with an array

Posted on 16th Feb 2014 07:03 pm by admin

Hi, I'm getting the temperature value off of the Environment Canada website along with the icon filename, so I can display my own icons and temperature on my site. All this works and I can display the temperature but my conditional statements aren't working to display my icons. I'm new to PHP and I don't see why this is a problem:
Code: <?php
$url = "http://www.weatheroffice.gc.ca/city/pages/on-69_metric_e.html";
$ch = curl_init();//Initialise CURL
curl_setopt($ch, CURLOPT_URL, $url);//Set the url
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);//We want it to return data
curl_setopt ($ch, CURLOPT_CONNECTTIMEOUT, 100);//Of course, we don't want your script to run forever, so set a timeout
$text = curl_exec($ch);//Execute and get the page

$exploded = explode('<p class="temperature">',$text);//Make an array of the part before and after the <title> tag
$result = explode('<sup>',$exploded[1]);//Grab the part after the <title> tag, and split that too

$exploded2 = explode('<img id="currentimg" src="/weathericons/',$text);//Make an array of the part before and after the <title> tag
$result2 = explode('.gif"',$exploded2[1]);//Grab the part after the <title> tag, and split that too

curl_close($ch);//Close cURL

if($result2[0] < "02"){
echo "<img src="images/weather/00.gif" alt="Sunny">";
}
if(($result2[0] > "01") && ($result2[0] < "09")) {
echo "<img src="images/weather/01.gif" alt="Cloudy with chance of showers">";
}
if($result2[0] == "09" || $result2[0] == "19" || $result2[0] == "39") {
echo "<img src="images/weather/03.gif" alt="Storm">";
}
if(($result2[0] > "9" && $result2[0] < "9") || ($result2[0] > "19" && $result2[0] < "25") || ($result2[0] > "26" && $result2[0] < "30") || ($result2[0] > "31" && $result2[0] < "39")) {
echo "<img src="images/weather/02.gif" alt="Cloudy with chance of showers">";
}
if(($result2[0] > "24" && $result2[0] < "27") || ($result2[0] > "29" && $result2[0] < "32") || ($result2[0] > "39") {
echo "";
}
else{
echo "";
}
echo $result[0];//Echo the result
?>

Your Answer:

Login to answer

Other forums

User input in to variable
Hi all,

I'm sure this is very easy but I'm having another brain freeze!

At the end of

Formatting echo from database
So I have a database that stores First and last names, then echos them back to a website, as of now

weeks in a year
hi,

i found this snippet on php.net
QuoteFor the week number for weeks starting on Sunday:

str_replace help
Hey there,

I'm a PHP newb, I'm having troubles with the str_replace function. I want to clean

DataTable Help Required
Hi all I am creating an app that utilises and MS Access back end and queries it quite a bit at vario

Rss feed question
Hi

My blog and my website are different. Am i able to take my rss feed
from my blog and p

Looking for help reading a .txt or .ini file and outputting the info.
I have a file called Info.ini and It has the following info:
Code: [General]
Online=0
I wou

Is this possible? If one file assigned to an ID...
I have a page that lists property listings assigned to a specific user (a manage page), with brief t

can i optmize image to 50% quality before uploading 2 server
Hi there

i have jus written a php program to upload and display images but when i try to uplo

problems with script
I made a small script wich exchanges points in my website:


<?php
session_start