Quick fix: Conditional statement with an array


Posted on 16th Feb 2014 07:03 pm by admin

Hi, I'm getting the temperature value off of the Environment Canada website along with the icon filename, so I can display my own icons and temperature on my site. All this works and I can display the temperature but my conditional statements aren't working to display my icons. I'm new to PHP and I don't see why this is a problem:
Code: <?php
$url = "http://www.weatheroffice.gc.ca/city/pages/on-69_metric_e.html";
$ch = curl_init();//Initialise CURL
curl_setopt($ch, CURLOPT_URL, $url);//Set the url
curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1);//We want it to return data
curl_setopt ($ch, CURLOPT_CONNECTTIMEOUT, 100);//Of course, we don't want your script to run forever, so set a timeout
$text = curl_exec($ch);//Execute and get the page

$exploded = explode('<p class="temperature">',$text);//Make an array of the part before and after the <title> tag
$result = explode('<sup>',$exploded[1]);//Grab the part after the <title> tag, and split that too

$exploded2 = explode('<img id="currentimg" src="/weathericons/',$text);//Make an array of the part before and after the <title> tag
$result2 = explode('.gif"',$exploded2[1]);//Grab the part after the <title> tag, and split that too

curl_close($ch);//Close cURL

if($result2[0] < "02"){
echo "<img src="images/weather/00.gif" alt="Sunny">";
}
if(($result2[0] > "01") && ($result2[0] < "09")) {
echo "<img src="images/weather/01.gif" alt="Cloudy with chance of showers">";
}
if($result2[0] == "09" || $result2[0] == "19" || $result2[0] == "39") {
echo "<img src="images/weather/03.gif" alt="Storm">";
}
if(($result2[0] > "9" && $result2[0] < "9") || ($result2[0] > "19" && $result2[0] < "25") || ($result2[0] > "26" && $result2[0] < "30") || ($result2[0] > "31" && $result2[0] < "39")) {
echo "<img src="images/weather/02.gif" alt="Cloudy with chance of showers">";
}
if(($result2[0] > "24" && $result2[0] < "27") || ($result2[0] > "29" && $result2[0] < "32") || ($result2[0] > "39") {
echo "";
}
else{
echo "";
}
echo $result[0];//Echo the result
?>

No comments posted yet

Your Answer:

Login to answer
212 Like 7 Dislike
Previous forums Next forums
Other forums

I think i'm using the syntax incorrectly
Hi Everyone!

I'm new to this forum and a newbie with PHP - I'm glad I found this site - I hop

string to currency format
Hi guys...

Actually I chunk out some data from txtfile and one of the data contains amount va

Help with captcha script needed
Hello,

I am working on a script where reCAPTCHA or a similar form of CAPTCHA will be used, f

Suggestions for Functional module
Hello experts,
I Have done B.Sc(Mathematics) and MCA & have learnt SAP/ABAP but do n

How to insert random unique values in 2 columns ?
I have table with 2 columns

Create Table code_for_code (
first_code varchar2(10) uni

BSP Ext - tableView - Sort - NEWBIE
Hi,
I have been trying to get the sort to work. I have defined the column definitions by fillin

Undefined Variable: PHP_SELF, pls help
Hi,

Im a newbie on PHP / MySQL programming and Im running a script to search one field on my

Multiple PHP errors when clicking a link..and..removing a ghost..
Hi - I have 2 problems with a new website - homeswapvacations.com, which I need help solving.

UTL File problem
Hi
I have a file in certain path with the following permissions (The file is a dummy file witho

php redirecting
i wont open a new thread but i have a question about redirecting....
i wonder why my code doesnt

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash