tell csv import script to ignore blank rows?


Posted on 16th Feb 2014 07:03 pm by admin

Hi i have the below script but i get an error if a row is blank ie a return in the csv file at the end i need to somehow tell it to skip the rows that have nothing on them:

Code: <?php
// define table name and csv file location and name

$supp_id = "15";
$pricecode = "6";
$csvupload = "../ccd/Catalogue_ZZMILGAT.csv";

// create DB connection
$host = "localhost";
$user = "user";
$pass = "pass";
$mydb = "db";
$table = "table";

$db = mssql_connect($host,$user,$pass);
mssql_select_db($mydb);

// delete all old data
$sql2 = "DELETE FROM ".$table." WHERE supp_id = ".$supp_id."";

mssql_query($sql2) or die("Failed to insert to db ");

// Define DB mapping (Fill in rest of the mapping in order of appearance in CSV)
$fields = array(
"manufacturer",
"ignore",
"manf_part_no",
"supp_part_no",
"description",
"rrp",
"cost_price",
"avail_qty");


// Open the CSV file
$handle = fopen($csvupload, "r") or die("Unable to open $csvupload for reading");

// Get each row's values to an array
$i = 1;
// define tab delimited or comma
while (($data = fgetcsv($handle, 512, ",")) !== FALSE) {
// First row's headers and not included, otherwise row field count must match wanted field count
if(count($data)==count($fields) && $i!=1){
$rows[] = $data;
}
elseif(count($data)!=count($fields)) {
die("Erroneus CSV file: incorrect field count on row $i");
}
$i++;
}

// Close file handle
fclose($handle);

// Create SQL
if(count($rows)==0) die("No rows found in user file");


// Remove last comma
foreach($rows as $i => $row){
$sql = "INSERT INTO ".$table." (";
foreach($fields as $field)
if($field!="ignore")
$sql .= "$field,";
$sql = substr($sql,0,-1).",supp_id, date_added, PriceCode) VALUES ";
$sql .= "(";
foreach($row as $j => $value){
if($fields[$j]!="ignore"){
if(empty($value))
$value = "0";
// Quote strings, try to remove existing quotes
elseif(!is_numeric($value))
$value = str_replace("'","",$value);
$value = str_replace(""","",$value);
$sql .= "'$value',";
}
}

$sql = substr($sql,0,-1).",'".$supp_id."', getdate(),'".$pricecode."')"; // Remove last comma
//echo "SQL became: $sql";

mssql_query($sql) or die("Failed to insert to db ");

}

?>

No comments posted yet

Your Answer:

Login to answer
110 Like 17 Dislike
Previous forums Next forums
Other forums

Troubles with a spider class
I am building a spider that will crawl through random whitepages (eg. anywho.com, switchboard.com, w

close site for maintenance
i get a tutorial, saying the following code can put our site offline, and only the developer can vie

need help with php get
i have a option box that gets filled with dates, but how do i get once the option value has been cli

Can't seem to capture a variable in a chained select
I'm *this* close to having a chained select running but for some reason it doesn't seem to be pickin

Forms Authentication and Refresh at Login page
Hello, When I try to press the Login button in my webapplication at my login.aspx page nothing h

Hyperlink in PHP to MySQL record
Hello,

I am having trouble as i am new to php. I have connected to the database and I have di

PHP page is blank
Hi Everyone,

I have a site in which I am able to open the first PHP webpage in my browser but

image upload script not working with png
The basic process of this php code is to take the submitted file, convert it to a small JPG thumbnai

count only commas outside parenteses
I have a sql table containing
id - query - query name
the first page contains a drop down men

preg_match logical error
Code: <?php
$s = file_get_contents("page.html");
preg_match('/<div cla

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash