tell csv import script to ignore blank rows?


Posted on 16th Feb 2014 07:03 pm by admin

Hi i have the below script but i get an error if a row is blank ie a return in the csv file at the end i need to somehow tell it to skip the rows that have nothing on them:

Code: <?php
// define table name and csv file location and name
Did you know?Explore Trending and Topic pages for more stories like this.

$supp_id = "15";
$pricecode = "6";
$csvupload = "../ccd/Catalogue_ZZMILGAT.csv";

// create DB connection
$host = "localhost";
$user = "user";
$pass = "pass";
$mydb = "db";
$table = "table";

$db = mssql_connect($host,$user,$pass);
mssql_select_db($mydb);

// delete all old data
$sql2 = "DELETE FROM ".$table." WHERE supp_id = ".$supp_id."";

mssql_query($sql2) or die("Failed to insert to db ");

// Define DB mapping (Fill in rest of the mapping in order of appearance in CSV)
$fields = array(
"manufacturer",
"ignore",
"manf_part_no",
"supp_part_no",
"description",
"rrp",
"cost_price",
"avail_qty");


// Open the CSV file
$handle = fopen($csvupload, "r") or die("Unable to open $csvupload for reading");

// Get each row's values to an array
$i = 1;
// define tab delimited or comma
while (($data = fgetcsv($handle, 512, ",")) !== FALSE) {
// First row's headers and not included, otherwise row field count must match wanted field count
if(count($data)==count($fields) && $i!=1){
$rows[] = $data;
}
elseif(count($data)!=count($fields)) {
die("Erroneus CSV file: incorrect field count on row $i");
}
$i++;
}

// Close file handle
fclose($handle);

// Create SQL
if(count($rows)==0) die("No rows found in user file");


// Remove last comma
foreach($rows as $i => $row){
$sql = "INSERT INTO ".$table." (";
foreach($fields as $field)
if($field!="ignore")
$sql .= "$field,";
$sql = substr($sql,0,-1).",supp_id, date_added, PriceCode) VALUES ";
$sql .= "(";
foreach($row as $j => $value){
if($fields[$j]!="ignore"){
if(empty($value))
$value = "0";
// Quote strings, try to remove existing quotes
elseif(!is_numeric($value))
$value = str_replace("'","",$value);
$value = str_replace(""","",$value);
$sql .= "'$value',";
}
}

$sql = substr($sql,0,-1).",'".$supp_id."', getdate(),'".$pricecode."')"; // Remove last comma
//echo "SQL became: $sql";

mssql_query($sql) or die("Failed to insert to db ");

}

?>
No comments posted yet

Your Answer:

Login to answer
110 Like 17 Dislike
Previous forums Next forums
Other forums

Display error above the login forum help!
Hi guys. just so you know im not asking for someone to do this for me I just need to be pointed in t

pull content
I have an existing page, domain/adverts.php which has a good PR. I've just rebuilt my site and the n

Multi image upload
I have a gallery to build and want to build a dynamic upload form to allow for $var number of fields

help me fix these syntax errors...
I keep getting multiple syntax errors on this script like this one:

Parse error: syntax error

Where am I going wrong
Been trying to work this out for hours

I have two tables called 'Genres' and 'Films'. Genre

quick question
Hi ..

i have a question
how do i set a var so it displays via an echo
Code: $logo = '&a

Trouble checking SESSION cookie
I am trying to use $_SESSION cookies to verify admin privileges .
I don't understand why this is

Open/Close Links in Php
Hello, Hoping someone can inform me how I can get PHP to automatically open a set of links in a new

query based on 2 conditions
I want to select if the doc_type is either s OR f but this doesn't work:

Code: [Select]$query

first id from db not showing
I have a php script which displays the content of a mysql table as a html table with sorting, delete

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash