Problem assigning value to variable in "IF" function
Does this script makes sense? I am trying to take the value that is set to "authenticat" a
Hom to make one url to open together with another url
I have a chat, which i want to be opened, as soon as the users login to the site. As it is now, when
Something like an INI editor or a DelimitedText-Editor
Hi all,
Am very, very, very new to PHP and not sure if I should be posting this to a Javascri
IF STATEMENT HELP
Hi
i have created a calendar from a table:
Code: Calendar: October 2009
<table w
Strange array issue, never happened before.
mysql_fetch_array returns 1 array per call. Generally that's why it is inserted into a while statem
CODE NOT WORKING
Code: [Select]<?php
//include shared codes
include '../lib/common.php';
include
My query is being run with no results.
I have this.
Code: function DropUser($duser_id, $user_email, $user_username) {
why isn't this PHP code working ???
it's suppose to find a name on the database.
<?php
$s = $_POST["lname&
Need Help with a query
Hello,
For some reason I am just not getting the right answer when I do this query and not quite
include problem
I have my root folder as:
Code: $root = $_SERVER["SITE_HTMLROOT"]; // the server root<