pageination not working right... coping images over 4 pages
Posted on
16th Feb 2014 07:03 pm by
admin
Code: <?php //This code will obtain the required page number from the $_GET array. Note that if it is not present it will default to 1.
if (isset($_GET['pageno'])) {
$pageno = $_GET['pageno'];
} else {
$pageno = 1;
} // if
//This code will count how many rows will satisfy the current query.
$query ="SELECT * FROM `photos` WHERE `thumb_id` = '3'";
$result = mysql_query($query) or trigger_error("SQL", E_USER_ERROR);
$query_data = mysql_fetch_row($result);
$numrows = $query_data[0];
//This code uses the values in $rows_per_page and $numrows in order to identify the number of the last page.
$rows_per_page = 3;
$lastpage = ceil($numrows/$rows_per_page);
//This code checks that the value of $pageno is an integer between 1 and $lastpage.
$pageno = (int)$pageno;
if ($pageno > $lastpage) {
$pageno = $lastpage;
} // if
if ($pageno < 1) {
$pageno = 1;
} // if
//This code will construct the LIMIT clause for the sql SELECT statement.
$limit = 'LIMIT ' .($pageno - 1) * $rows_per_page .',' .$rows_per_page;
//Now we can issue the database qery and process the result.
$sql="SELECT * FROM `photos` WHERE `thumb_id` = '3'";
$res = mysql_query($sql) or die(mysql_error());
echo "<table>";
$i = 0;
while($row = mysql_fetch_assoc($res)){
$i++;
if ($i % 3 == 0)
echo '<tr>';
echo "<td> <img src="http://www.runningprofiles.com/members/include/myimages/thumbs/" . $row['picurl'] . "" /></a><br /> </td>";
if ($i % 3 == 0)
echo '</tr>';
if( $i == 9 ) break;
}
echo "</table>";
//... process contents of $result ...
//Finally we must construct the hyperlinks which will allow the user to select other pages. We will start with the links for any previous pages.
if ($pageno == 1) {
echo " FIRST PREV ";
} else {
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=1'>FIRST</a> ";
$prevpage = $pageno-1;
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=$prevpage'>PREV</a> ";
} // if
//Next we inform the user of his current position in the sequence of available pages.
echo " ( Page $pageno of $lastpage ) ";
//This code will provide the links for any following pages.
if ($pageno == $lastpage) {
echo " NEXT LAST ";
} else {
$nextpage = $pageno+1;
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=$nextpage'>NEXT</a> ";
echo " <a href='http://www.runningprofiles.com/members/index.php?page=album&pageno=$lastpage'>LAST</a> ";
} // if
?>
Im alittle confused by my pageinated results... i only have 2 images... and for some reason its repeated these images over 11 pages... how comes?
No comments posted yet
Your Answer:
Login to answer
347
43
Other forums
Strip Slashes Help
I've got a script that i've downloaded of the net to edit multiple fields from my sql database, and
Facebook status update API
Hello,
So, I'm trying to create my first Facebook application with PHP.
Basic ideas fo
quick question
Hi ..
i have a question
how do i set a var so it displays via an echo
Code: $logo = '&a
Preg_match question
I want to use preg_match to make sure a string is always 6 characters long and only contains 0-9 and
The type or namespace name 'ServiceModel' does not exist in the namespace 'System'
When I locally run the website, it works just fine, but when I uploaded it to the hosting environmen
a function to check directory depth
I'm working on a php script to upload files in to a set directory.
the user can select to upload
get font info from a font file
hello,
Does anyone know how to get font info from a font file ... using php of course !
<
Sub-domains & calling unique content
Hello,
Is there a way use something similar to the $_GET function for a sub-domain? I to be a
Check something, wait, check again, do something!
Hi guys.
I wonder if someone can help me with this.
Basically, what I want to do is (
Displaying data from MySql a different way
Hi all,
I'm pretty new to php and MySql and have hit a problem.
I am able to display data