Pagination

Posted on 16th Feb 2014 07:03 pm by admin

Okay here is the page in question: http://blenderteachings.000a.biz/tutorials.hamishhill.php

I have the records in a database(tutorial name, username description etc). I am pulling these and displaying them but i need them to be set out like this http://blenderteachings.000a.biz/index.php

But my code doesnt do it like that. Any ideas?

Heres the code:

Code: <?php

ob_start();
include('header.php');
include('db.php');
$db=mysql_connect($db_host,$db_user,$db_pass)
or die ('I cannot connect to the database because: ' . mysql_error());
mysql_select_db($db_name,$db);

if (!(isset($pagenum)))
{
$pagenum = 1;
}


$data = mysql_query("SELECT * FROM tutorials") or die(mysql_error());
$rows = mysql_num_rows($data);

$page_rows = 3;

$last = ceil($rows/$page_rows);

if ($pagenum < 1)
{
$pagenum = 1;
}
elseif ($pagenum > $last)
{
$pagenum = $last;
}

$max = 'limit ' .($pagenum - 1) * $page_rows .',' .$page_rows;


$sql = "SELECT username, fullname, description, link
FROM tutorials
WHERE username='hamsterhill' $max";

$result = mysql_query($sql);
while ($row = mysql_fetch_assoc($result)) {
?>

<div id="page">
<div id="content">

<div class="post">
<p class="meta"><?php echo $row["fullname"] . ' | ' .$row["username"]; ?>
<img src="images/img08.png" alt="bullet"></p>

<div class="entry">
<?php echo $row['description']; echo '<br />'; } ?>
</div>
</div>

<?php
echo " Page $pagenum of $last <p>";

if ($pagenum == 1)
{
}
else
{
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=1'> <<-First</a> ";
echo " ";
$previous = $pagenum-1;
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$previous'> <-Previous</a> ";
}


//This does the same as above, only checking if we are on the last page, and then

generating the Next and Last links
if ($pagenum == $last)
{
}
else {
$next = $pagenum+1;
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$next'>Next -></a> ";
echo " ";
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$last'>Last ->></a> ";
}
?>
</div>

<?php include('footer.php');
ob_flush();
mysql_close($db);
?>

Your Answer:

Login to answer

Other forums

TCP Sending Unsigned Char...
Hi...

I want to send over tcp/ip some data, i have the data in hexadecimal, and when i tr

Javascript form submit and radio buttons?
When this form is submitted, it is automatically resubmitted using JS.

All my fields are carr

Getting a variable to work in function params
I have this fuction which is inside a class:

Code: public static function generateEmbedCode($

Parse Error Help
Hello, I got the parse error "Parse error: syntax error, unexpected ',' in register.php on line

Parse multirow HTML table
Hello all,
I have a site I am working on. Its a sports site and I am trying to add stats to a DB

IP Based Cron Jobs
I run cronjobs on my website. After one of my visitors got curious and tinkered around he realized h

PHP File Upload Problem
Hi, I have written a very simple file upload script but it fails for reasons I can't explain. Hope

Help with writing "$" with fopen
I just can't get my syntax correct. Could someone help me please? I am trying to write a connect fil

PHP search multiple input field box help
I am having a problem with my search script. At current it will simply search by a selected date whi

Problem with HTML form
Hello,

I made a HTML form with some fields and check box.
Everything works fine except whe