Pagination

Posted on 16th Feb 2014 07:03 pm by admin

Okay here is the page in question: http://blenderteachings.000a.biz/tutorials.hamishhill.php

I have the records in a database(tutorial name, username description etc). I am pulling these and displaying them but i need them to be set out like this http://blenderteachings.000a.biz/index.php

But my code doesnt do it like that. Any ideas?

Heres the code:

Code: <?php

ob_start();
include('header.php');
include('db.php');
$db=mysql_connect($db_host,$db_user,$db_pass)
or die ('I cannot connect to the database because: ' . mysql_error());
mysql_select_db($db_name,$db);

if (!(isset($pagenum)))
{
$pagenum = 1;
}


$data = mysql_query("SELECT * FROM tutorials") or die(mysql_error());
$rows = mysql_num_rows($data);

$page_rows = 3;

$last = ceil($rows/$page_rows);

if ($pagenum < 1)
{
$pagenum = 1;
}
elseif ($pagenum > $last)
{
$pagenum = $last;
}

$max = 'limit ' .($pagenum - 1) * $page_rows .',' .$page_rows;


$sql = "SELECT username, fullname, description, link
FROM tutorials
WHERE username='hamsterhill' $max";

$result = mysql_query($sql);
while ($row = mysql_fetch_assoc($result)) {
?>

<div id="page">
<div id="content">

<div class="post">
<p class="meta"><?php echo $row["fullname"] . ' | ' .$row["username"]; ?>
<img src="images/img08.png" alt="bullet"></p>

<div class="entry">
<?php echo $row['description']; echo '<br />'; } ?>
</div>
</div>

<?php
echo " Page $pagenum of $last <p>";

if ($pagenum == 1)
{
}
else
{
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=1'> <<-First</a> ";
echo " ";
$previous = $pagenum-1;
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$previous'> <-Previous</a> ";
}


//This does the same as above, only checking if we are on the last page, and then

generating the Next and Last links
if ($pagenum == $last)
{
}
else {
$next = $pagenum+1;
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$next'>Next -></a> ";
echo " ";
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$last'>Last ->></a> ";
}
?>
</div>

<?php include('footer.php');
ob_flush();
mysql_close($db);
?>

Your Answer:

Login to answer

Other forums

Images in email problem
I found this script for sending emails, it works but if the email has <img src="image.jp

serializing objects - loses methods - the point being?
Hi

I know that serializing an object will lose the methods. But whats the point in that? What

dinamic "textboxes"?
Ey all, my first post here, i hope its not a hard one

I display mysql results in a table

Calander Basic Spript help
hi, just starting out with PHP and have the following script:

<?php
//This gets t

Confusing Functions
So, I've been reading up on Functions and I like them! However, I need some help using variables in

New Login Script
Hi all, i attempted to create a whole new login script witch isnt working for some reason i dont kno

include problem
I have my root folder as:
Code: $root = $_SERVER["SITE_HTMLROOT"]; // the server root<

Functions Not Loading Into Div
I had some help doing some of this but what I'm trying to do is get my functions to retrieve its val

Email Script does not reach destination
Hey Guys look at this code snippet :
Code:
//read a line from the file

$myFile = "

redirect standard error and assert (how to?)
How do you redirect standard error and assert?

---

(Why? I am creating an web app and