Pagination

Posted on 16th Feb 2014 07:03 pm by admin

Okay here is the page in question: http://blenderteachings.000a.biz/tutorials.hamishhill.php

I have the records in a database(tutorial name, username description etc). I am pulling these and displaying them but i need them to be set out like this http://blenderteachings.000a.biz/index.php

But my code doesnt do it like that. Any ideas?

Heres the code:

Code: <?php

ob_start();
include('header.php');
include('db.php');
$db=mysql_connect($db_host,$db_user,$db_pass)
or die ('I cannot connect to the database because: ' . mysql_error());
mysql_select_db($db_name,$db);

if (!(isset($pagenum)))
{
$pagenum = 1;
}


$data = mysql_query("SELECT * FROM tutorials") or die(mysql_error());
$rows = mysql_num_rows($data);

$page_rows = 3;

$last = ceil($rows/$page_rows);

if ($pagenum < 1)
{
$pagenum = 1;
}
elseif ($pagenum > $last)
{
$pagenum = $last;
}

$max = 'limit ' .($pagenum - 1) * $page_rows .',' .$page_rows;


$sql = "SELECT username, fullname, description, link
FROM tutorials
WHERE username='hamsterhill' $max";

$result = mysql_query($sql);
while ($row = mysql_fetch_assoc($result)) {
?>

<div id="page">
<div id="content">

<div class="post">
<p class="meta"><?php echo $row["fullname"] . ' | ' .$row["username"]; ?>
<img src="images/img08.png" alt="bullet"></p>

<div class="entry">
<?php echo $row['description']; echo '<br />'; } ?>
</div>
</div>

<?php
echo " Page $pagenum of $last <p>";

if ($pagenum == 1)
{
}
else
{
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=1'> <<-First</a> ";
echo " ";
$previous = $pagenum-1;
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$previous'> <-Previous</a> ";
}


//This does the same as above, only checking if we are on the last page, and then

generating the Next and Last links
if ($pagenum == $last)
{
}
else {
$next = $pagenum+1;
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$next'>Next -></a> ";
echo " ";
echo " <a href='{$_SERVER['PHP_SELF']}?pagenum=$last'>Last ->></a> ";
}
?>
</div>

<?php include('footer.php');
ob_flush();
mysql_close($db);
?>

Your Answer:

Login to answer

Other forums

difference between datetimes
($row['totime']-$row['fromtime'])/60

this is giving me 0

example of totime and fromtim

SQL Query/echo not working
Hey all,

I'm trying to run (what I thought) was a simple operation and it isn't working. I h

PHP SUBMIT
Code: <input name="doLogin" type="image" src="images/loginsubmit.jpg

validating url
im trying to validate url's sent to me by a form
the url's im collecting are for placing banners

reading xml faster than DB call?
I am trying to optimize a high traffic website, and I enabled a feature where there are three photos

Dynamic memory problem
Hey,

At the beginning of my code, I have this line:

Shape* gShape = 0;

How to add functionality to a simple php calender?
Hello everyone,

I have just finished creating a simple php calander. Can someone point

how to validate date using javascript
I need to validate date in textbox using javascript..
The date is must be not greater than TODAY

Form a inline view based on the results of the previous query?
Hi Experts,
Can we form a inline view on the results of a previous query (another inline view)?

Need a Timecode Class...
Not a Time Stamp, Time Code. Format is a bit different. HH:MM:SS:FF where FF is Frames. I dont re