Where am I going wrong

Posted on 16th Feb 2014 07:03 pm by admin

Been trying to work this out for hours

I have two tables called 'Genres' and 'Films'. Genres contains two columns 'Genre_id' and 'Genre_Name'. Films contains a load of columns, the most important being 'Title', 'Year', Director', 'Genres'. Now im trying to create a page where the user can edit a film in the 'Films' table. I want this form to already be populated with the existing values which the user can then delete and enter new ones. Heres the code:

Code:
<?
include 'connect.php';
$FilmID= $_GET['id'];
$result = mysql_query("SELECT Films.*, Genres.Genre_id, Genres.Genre_Name FROM Films INNER JOIN Genres ON Films.Genres = Genres.Genre_id WHERE Films.Film_id = $FilmID" ,$linkme) or die ('Error: '.mysql_error ());

$row = mysql_fetch_array($result);
$current_Genre = $row['Genre_Name'];
$current_Genre_id = $row['Genre_id'];

?>
<form method="post" action="update2.php?id=<? echo $FilmID ?>">
<table>
<tr>
<td>Title</td>
<td><input name = "Title" value="<? echo $row['Title'] ?>" type="text" /></td>
</tr>
<tr>
<td>Year</td>
<td><input name = "Year" value="<? echo $row['Year'] ?>" type="text" /></td>
</tr>
<tr>
<td>Director</td>
<td><input name = "Director" value="<? echo $row['Director'] ?>" type="text" /></td>
</tr>
<tr><td>
Genre:</td><td> <select name="Genre">
<option value = "<?php echo $current_Genre_id ?>"> <? echo $current_Genre ?> </option>
<?
$result = mysql_query("SELECT * FROM Genres",$linkme) or die ('Error: '.mysql_error ());
while($row = mysql_fetch_array($result));
{ ?>
<option value = "<?php echo $row['Genre_id'] ?>"> <? echo $row['Genre_Name'] ?> </option>
<? } ?>
</select></td>
</tr>
</table>
<input name="Update" type="submit" value="Update" />
</form>
<?
include 'close.php';
?>
<a href = "../admin.php">Back</a>


and heres the second page that actually changes the values:

Code:
<?
include 'connect.php';
$Title = $_REQUEST["Title"];
$Year = $_REQUEST["Year"];
$Director = $_REQUEST["Director"];
$Genre = $_REQUEST["Genre"];
$FilmID = $_GET['id'];

$result = mysql_query("UPDATE Films SET Title = '$Title' , Year = '$Year', Director ='$Director', Genre ='$Genre' WHERE Film_id = '$FilmID'",$linkme);
include 'close.php';
?>
Record Updated<br />
<a href = "../admin.php">Back</a>


There are no errors, the values just dont show up in the form, Where am I going wrong??

Your Answer:

Login to answer

Other forums

php + mysql count consecutive data
I have a database of values and I want to work out how to display them if the values match a consecu

simple ping code
been searchin the site/web and found code thats simple but doesnt work.

I have a personal we

form help
this doesn't work. i want the form action to go the location.href of the submit button chosen.. how

help with contest script
I would like to code a contest script to my site but i don't know how. Could someone just give me pu

Auto install
Hi I have a directory lets say "apps" that I then have more folders ie "email",

defining website tags
Hi,

What would be the best way to define tags for my site, such as website title, url etc.

Automatically Detect Phone Model for WAP Jar Deployment
Making a wap site is fairly simple, but I'd like to know if there's a way to make it so that the wap

Displaying values from a SQL count...
Hi,
Easy enough question i just forget the exact method ..
I have ...

Code: //count win

adding 0 to numbers
Hey guys i need to create a 00001 number in a loop. Is there a better way of forcing a 5 digit numbe

Help: calling function
Hi,
Is it possible to call a php function on page close?
If yes, could you explain how and whe