Display search result

Posted on 16th Feb 2014 07:03 pm by admin

Hi!

I have a SQL database with information about albums and track (music).

This is where the user inputs a search term(entersearch.php): Code: <form name="form" action="displaysearchalbum.php" method="get">
<input type="text" name="getsearch" />
<input type="submit" name="Submit" value="search album" />
</form>
<br />
<h2>Search for track</h2>
<form name="form" action="displaysearchtrack.php" method="get">
<input type="text" name="getsearch2" />
<input type="submit" name="submit2" value="search track" />
</form>
And this is where the search result is displayed with links to a pages with more information about the album the user is interested in.

Code: <?php

// Get the search variable from URL
$var = @$_GET['getsearch'] ;
$trimmed = trim($var); //trim whitespace from the stored variable

// rows to return
$limit=20;

// check for an empty string and display a message.
if ($trimmed == "")
{
echo "<p>Please enter a search...</p>";
exit;
}

// check for a search parameter
if (!isset($var))
{
echo "<p>We dont seem to have a search parameter!</p>";
exit;
}

//connect to your database
mysql_connect("xxx","xxx","xxx"); //(host, username, password)

//specify database
mysql_select_db("xxx") or die("Unable to select database"); //select which database we're using

// Build SQL Query
$result = mysql_query("SELECT albumid, albumname FROM album WHERE albumname like '%$trimmed%'");
//$query = "SELECT albumname FROM album WHERE albumname='$trimmed'";

while ($row = mysql_fetch_array($result)) {

echo '<a href="albuminfo.php?albumid=' . $row[0] . '">' . $row[1] . '</a>';
echo "<p></p>";
}

?>
My problem is that I don't know how to transfer the information from displaysearchalbum.php to albuminfo.php about which album the information is going to be displayed. Preferably I would have a variable in albuminfo.php which contains the albumid in interest. I am a novice in php but think that the code I have so far written is working. Any ideas about necessary changes in the code I wrote or what kind of code I need for albuminfo.php would be helpful. I have not yet written any code for albuminfo.php because I am not quite sure how to.

Your Answer:

Login to answer

Other forums

Images in email problem
I found this script for sending emails, it works but if the email has <img src="image.jp

max() problem
I have a while loop to get image names.
Code: $imagequery = mysql_query("SELECT * FROM ad_i

HeaderSelectedCssClass not working
I have an accordian where I have a drop down list in the first pane and a grid in the second pane.

Detail Expenses Report by Cost Center
I would like to obtain a report out of SAP that shows a list of expenses by cost center that shows t

TinyMCE / Ajax Postback Problem
Hiya all,

I have a page which loads the TinyMCE editor. On the postback I obviously want to f

Trouble with a select list
Hello All!
I was wondering if any of you guys could help me with a small problem I'm having!

Why does first ever HttpSendRequest take longer?
I promise this isn't as simple as it sounds. I'm wondering why the the first ever call to HttpSendRe

Quick fix: Conditional statement with an array
Hi, I'm getting the temperature value off of the Environment Canada website along with the icon file

Fetching array then reversing it
Hi, I have a simple problem, I'll try to explain it as best I can:
News entries in my database ar

puting for loop in 1 value
hi ,

how do i put this code in 1 value:
Code: <?php
for ($i=1; $i<=5; $i