MYSQL gen help
Posted on
16th Feb 2014 07:03 pm by
admin
This is my Mysql gen. can anyone tell me why this echos
MID(networkset.networkid, 3, 3) AS "MNC" SELECT FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid
and not
SELECT MID(networkset.networkid, 3, 3) AS "MNC" FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid
heres the code:
$arr = array($date,$time,$latandlong,$satdata,$MCC,$MNC,$MCCMNC,$name,$callid,$lac,$bsic,$arfcn,$relvl,$c1,$c2,$rxq,$timing,$numres,$audio,$video,$image);
function select($arr){
foreach ($arr as $key => $value) {
if (is_null($value)) {
unset($arr[$key]);
}
}
$last_item = end($arr);
$last_item = each($arr);
reset($arr);
foreach($arr as $key => $value){
if($value == $last_item['value'] && $key == $last_item['key']){
echo ',';
}
print $value;
}
}
//echo '
';
/* FROM */
$fromdefault1=" scan JOIN gps ON scan.gpsid = gps.gpsid";
$fromdefault2=" JOIN gsmscanset ON scan.scanid = gsmscanset.scanid";
$fromdefault3="JOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid";
/* WHERE */
$wheredefault="scan.typeid = 4 AND
gsmcell.cellid = gsmcell.servingcellid";
if (isset($datebetween, $dateand)){$datesearch=' AND DATE(gps.date) BETWEEN '.$datebetween.' AND '.$dateand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($lat, $long)){$latandlongsearch=' AND DATE(gps.time) BETWEEN '.$lat.' AND '.$long.'';}
/* Query */
$query = "
SELECT ".select($arr)."
FROM ".$fromdefault1.$namefrom.$fromdefault2.$fromdefault3.$numresform1.$numresform2.$audiofrom.$videofrom.$imagefrom."
WHERE ".$wheredefault.$datesearch.$timesearch.$latandlongsearch . "
";
echo $query;
}
Thank
No comments posted yet
Your Answer:
Login to answer
204
14
Other forums
delete comma
HI,
How to delete "," at the end of the string.
Code: $match = 2009/02/03/a2corr
help with email script...
hey
I need help with my mail script
when the form on http://www.mcgdesignstudio.com/c
Array disappearing in foreach loop
Okay, I have this problem where an array will become undefined in a foreach loop.
Here is the
How to assign a textbox value to PHP variable??
Hi ! Can any one help me out as quickly as possible. As I m new to PHP.
Plz tell me how to assign
Need help: how to catch acess of undefined class properties
Hello. I am learning OO with PHP and have hit a problem.
Some code runs as perfectly valid code,
Displaying values from a SQL count...
Hi,
Easy enough question i just forget the exact method ..
I have ...
Code: //count win
Call db table from any PHP file
Hi,
I want to be able to call a database table that will be setup in another file called init
Ajax not working on IE 6 for Windows CE
I've created a webpage which uses the classis Ajax in following format:view plaincopy to clipboardpr
HTML form problem
Ive made a form to that i want to send to my email via PHP. but when it send only the name's etc sen
PHP & Java
Hello,
can PHP code be used inside java code?
Code: <SCRIPT LANGUAGE="Java