MYSQL gen help
Posted on
16th Feb 2014 07:03 pm by
admin
This is my Mysql gen. can anyone tell me why this echos
MID(networkset.networkid, 3, 3) AS "MNC" SELECT FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid
and not
SELECT MID(networkset.networkid, 3, 3) AS "MNC" FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid
heres the code:
$arr = array($date,$time,$latandlong,$satdata,$MCC,$MNC,$MCCMNC,$name,$callid,$lac,$bsic,$arfcn,$relvl,$c1,$c2,$rxq,$timing,$numres,$audio,$video,$image);
function select($arr){
foreach ($arr as $key => $value) {
if (is_null($value)) {
unset($arr[$key]);
}
}
$last_item = end($arr);
$last_item = each($arr);
reset($arr);
foreach($arr as $key => $value){
if($value == $last_item['value'] && $key == $last_item['key']){
echo ',';
}
print $value;
}
}
//echo '
';
/* FROM */
$fromdefault1=" scan JOIN gps ON scan.gpsid = gps.gpsid";
$fromdefault2=" JOIN gsmscanset ON scan.scanid = gsmscanset.scanid";
$fromdefault3="JOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid";
/* WHERE */
$wheredefault="scan.typeid = 4 AND
gsmcell.cellid = gsmcell.servingcellid";
if (isset($datebetween, $dateand)){$datesearch=' AND DATE(gps.date) BETWEEN '.$datebetween.' AND '.$dateand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($lat, $long)){$latandlongsearch=' AND DATE(gps.time) BETWEEN '.$lat.' AND '.$long.'';}
/* Query */
$query = "
SELECT ".select($arr)."
FROM ".$fromdefault1.$namefrom.$fromdefault2.$fromdefault3.$numresform1.$numresform2.$audiofrom.$videofrom.$imagefrom."
WHERE ".$wheredefault.$datesearch.$timesearch.$latandlongsearch . "
";
echo $query;
}
Thank
No comments posted yet
Your Answer:
Login to answer
204
14
Other forums
Need help to identify this error please
:confused:Can anyone help me tell what this error message means? Maybe tell me where to look to fix
DATEDIFF Question
First time post, and of course it is a help question.
I am using a WP plug-in to display prev
Why is the logic of this simple code not working?
Hey, I'm trying to determine if a table already exists in mysql, but doing a query first with mysql_
Legal Issues for SAP ERP o ERP in general
Hi experts,
Can someone please help me finding some documentation about legal issues tha
Problem with PHP code- simple contact form
I'm relativily new to PHP; I know HTML and CSS stuff but I have a problem- I have a contact form wit
Hyperlink in PHP to MySQL record
Hello,
I am having trouble as i am new to php. I have connected to the database and I have di
question about header() security
is is safe to just use the header() function to redirect someone if they are, say, not logged in? or
Problem with HTML form
Hello,
I made a HTML form with some fields and check box.
Everything works fine except whe
login and redirect
hello! can someone help me.. can you give me an idea.. I want to make a login page and redirects it
webpage with (simple) login & mysql-db
Hi all,
What I was looking for before was a multi-user password manager, web-based! The offer