MYSQL gen help
Posted on
16th Feb 2014 07:03 pm by
admin
This is my Mysql gen. can anyone tell me why this echos
MID(networkset.networkid, 3, 3) AS "MNC" SELECT FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid
and not
SELECT MID(networkset.networkid, 3, 3) AS "MNC" FROM scan JOIN gps ON scan.gpsid = gps.gpsid JOIN gsmscanset ON scan.scanid = gsmscanset.scanidJOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid WHERE scan.typeid = 4 AND gsmcell.cellid = gsmcell.servingcellid
heres the code:
$arr = array($date,$time,$latandlong,$satdata,$MCC,$MNC,$MCCMNC,$name,$callid,$lac,$bsic,$arfcn,$relvl,$c1,$c2,$rxq,$timing,$numres,$audio,$video,$image);
function select($arr){
foreach ($arr as $key => $value) {
if (is_null($value)) {
unset($arr[$key]);
}
}
$last_item = end($arr);
$last_item = each($arr);
reset($arr);
foreach($arr as $key => $value){
if($value == $last_item['value'] && $key == $last_item['key']){
echo ',';
}
print $value;
}
}
//echo '
';
/* FROM */
$fromdefault1=" scan JOIN gps ON scan.gpsid = gps.gpsid";
$fromdefault2=" JOIN gsmscanset ON scan.scanid = gsmscanset.scanid";
$fromdefault3="JOIN gsmcell ON gsmscanset.cellid = gsmcell.cellid";
/* WHERE */
$wheredefault="scan.typeid = 4 AND
gsmcell.cellid = gsmcell.servingcellid";
if (isset($datebetween, $dateand)){$datesearch=' AND DATE(gps.date) BETWEEN '.$datebetween.' AND '.$dateand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($timebetween, $timeand)){$timesearch=' AND DATE(gps.time) BETWEEN '.$timebetween.' AND '.$timeand.'';}
if (isset($lat, $long)){$latandlongsearch=' AND DATE(gps.time) BETWEEN '.$lat.' AND '.$long.'';}
/* Query */
$query = "
SELECT ".select($arr)."
FROM ".$fromdefault1.$namefrom.$fromdefault2.$fromdefault3.$numresform1.$numresform2.$audiofrom.$videofrom.$imagefrom."
WHERE ".$wheredefault.$datesearch.$timesearch.$latandlongsearch . "
";
echo $query;
}
Thank
No comments posted yet
Your Answer:
Login to answer
204
14
Other forums
php wont update my db
hello,
sorry for posting in mysql forum but i dont know where exactly is the problem but here
Multidimensional array problems in $_POST
I'm having trouble with a three-dimensional $_POST array. It starts as a two-dimensional array on th
Email to a friend script problems
I have this send-to-a-friend script with 2 issues:
1) When you open the form popup on a p
Include a php
Hello,
I'm trying to include a function that shows the recent searches.
Example I have <
Php - mysql store data and use it later?
Hi, i' making a login page at the moment, however my username + password is stored many different pl
How to get the previous months last date....
Here's my wittle problem. I suck at working with dates.
So today is 10/20/2009, i need to fig
Find current logon time
Hi,
in my sql script i want to query and find out the logon time of the current session.
<
Save cookie to DB
I'm working on a pixel tracking script for an incentive website and I need to use an ASP script to s
How to convert this array to string
I am having problems converting this array to a string
using print_r($val[1]); I get:
Code: [
Get content from table into a list, without repeating.
Alright this is kinda an odd thing, so I need some help.
I have a table "quote" wit