PHP Code reffering to database, doing something wrong.. pls help
Posted on
16th Feb 2014 07:03 pm by
admin
Well i am quite new with PHP
and for school we have to make a PHP script which reffers to a Database,
Well, more explicit, we have this form showing all "employees"
last name etc.
made it week before,
and we had to add a new bar to also upload pictures and show them.
So i made this script but it won't work.
And maybe it's just me being stupid..
But please help me
EDIT: it's obvious that pictures reffers to the picture iwant to upload and show.
2nd EDIT: Found out i missed a " , "
Well now the problem is that when i run it and try to upload a picture i won't see anything
<?php
function displayAllEmployees() {
$sql = "SELECT * FROM `Employees` ORDER BY `LastName`";
$result = mysql_query($sql);
echo"<h1>Werknemers</h1>";
echo"<br/>";
echo"<input type="button" onclick="document.location.href='?action=addemployee';" value="Werknemer toevoegen" />";
echo"<br/>";
echo"<br/>";
echo"<table>";
echo" <tr>";
echo" <th>Employee ID</td>";
echo" <th>Last Name</td>";
echo" <th>Phone Number</td>";
echo" <th>Foto</td>";
echo" <th>Actie</td>";
echo" </tr>";
while($row = mysql_fetch_assoc($result)) {
$row = escapeArray($row);
echo" <tr>";
echo" <td>".$row['EmployeeID']."</td>";
echo" <td>".$row['LastName']."</td>";
echo" <td>".$row['PhoneNumber']."</td>";
echo" <td>".$row['Picture']."</td>";
echo" <td>";
echo" <a href="index.php?action=editemployee&id=".$row['EmployeeID']."">Bewerken</a>";
echo" |";
echo" <a href="javascript:confirmAction('Zeker weten?', 'index.php?action=deleteemployee&id=".$row['EmployeeID']."');">Verwijderen</a>";
echo" </td>";
echo" </tr>";
}
echo"</table>";
}
function displayAddEmployee() {
echo"<h1>Werknemer bewerken</h1>";
echo" <form method="post" action="index.php?action=insertemployee">";
echo" <table>";
echo" <tr>";
echo" <td>werknemernummer:</td>";
echo" <td><input type="text" name="EmployeeID" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>achternaam:</td>";
echo" <td><input type="text" name="LastName" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>telefoonnummer:</td>";
echo" <td><input type="text" name="PhoneNumber" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>Foto:</td>";
echo" <td><input type="file" name="Picture" /></td>";
echo" </tr>";
echo" <td></td>";
echo" <td><input type="submit" value="Opslaan" /></td>";
echo" </tr>";
echo" </table>";
echo" </form>";
}
function displayEditEmployees() {
$sql = sprintf( "SELECT * FROM `Employees` WHERE `EmployeeID` = %d",
mysql_escape_string($_GET['id']) );
$result = mysql_query($sql);
if($row = mysql_fetch_assoc($result)) {
$row = escapeArray($row);
echo"<h1>Werknemer bewerken</h1>";
echo" <form method="post" action="index.php?action=updateemployee">";
echo" <table>";
echo" <tr>";
echo" <td>Titel:</td>";
echo" <td><input type="text" name="EmployeeID" value="".$row['EmployeeID']."" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>Achternaam:</td>";
echo" <td><input type="text" name="LastName" value="".$row['LastName']."" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>Telefoon Nummer:</td>";
echo" <td><input type="text" name="PhoneNumber" value="".$row['PhoneNumber']."" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td>Foto:</td>";
echo" <td><input type="text" name="Picture" value="".$row['Picture']."" /></td>";
echo" </tr>";
echo" <tr>";
echo" <td></td>";
echo" <td><input type="submit" value="Opslaan" /></td>";
echo" </tr>";
echo" </table>";
echo" <input type="hidden" name="EmployeeID" value="".$row['EmployeeID']."" />";
echo" </form>";
}
else {
die("Geen gegevens gevonden");
}
}
function addEmployee() {
$sql = sprintf("INSERT INTO `Employees` (`EmployeeID`, `LastName`, `PhoneNumber`) VALUES ('%s', '%f', '%f', '%f')",
mysql_escape_string($_POST['EmployeeID']),
mysql_escape_string($_POST['LastName']),
mysql_escape_string($_POST['PhoneNumber']),
mysql_escape_string($_POST['Picture']) );
mysql_query($sql);
header("location: index.php?action=employees");
exit();
}
function updateEmployees() {
$sql = sprintf("UPDATE `Employees` SET
`EmployeeID` = '%s',
`LastName` = '%s',
`PhoneNumber` = '%s'
`Picture` = '%s'
WHERE `EmployeeID` = %d",
mysql_escape_string($_POST['LastName']),
mysql_escape_string($_POST['PhoneNumber']),
mysql_escape_string($_POST['EmployeeID'])
mysql_escape_string($_POST['Picture']) );
mysql_query($sql);
header("location: index.php?action=employees");
exit();
}
function deleteEmployees() {
$sql = sprintf("DELETE FROM `Employees` WHERE `EmployeeID` = %d", mysql_escape_string($_GET['id']));
mysql_query($sql);
header("location: index.php?action=employees");
exit();
}
?>
No comments posted yet
Your Answer:
Login to answer
221
11
Other forums
Local file browser with php
Halo..
So this is what i want to create. I have a folder that i share and it has many movies.
problem with php server update from mid 2009
Hi,
I have this navigation menu on 2 websites which used to work just fine. After a recent up
Get Total From While Loop
I'm trying to get the total for each product and add them for a Grand Total to list outside the loop
Referential Integrity problem when inserting into 2 tables at same time
Hello Everyone,
Im relativity new to PHP and MySQL and i have come up against a problem. i h
Login Functionality Working Different on IE
This is an odd one, I have a site which has an admin section. The admin pages unsurprisingly require
I got my hosting suspended XD
So I saw this challenge a day or so ago
http://www.programming-challenges.com/pg.php?page=dow
SQl num_rows problem
when i try to count rows from an SQL select i get an warning
Code: [Select]$countviews = mysq
paginate search result
Hi, I have a paginations script to display data from my database but i would like to paginate someon
Multi Level Array Problem
hi all,
For example I have array like below:
$temp = array(array('north america', 'us'
Socket Server Response Headers
Earlier I had a post about my Socket Server, I wasn't able to get it to connect, now I can
I