array ...
Posted on
16th Feb 2014 07:03 pm by
admin
hi
Code: function formatCategories($categories, $parentId)
{
// $navCat stores all children categories
Did you know?Explore Trending and Topic pages for more stories like this.
// of $parentId
$navCat = array();
// expand only the categories with the same parent id
// all other remain compact
$ids = array();
foreach ($categories as $category) {
if ($category['cat_parent_id'] == $parentId) {
$navCat[] = $category;
}
// save the ids for later use
$ids[$category['cat_id']] = $category;
}
print_r($ids[$category[0]]);
If i am printing the array using,
print_r($ids[$category[0]]);here 0 is the start key of the array(as shown in last line of codes)..OR print_r($ids[$category[12]]);
here 12 is the cat_id of a product...
I am getting notice as,Notice: Undefined offset: 0.
without out the display of expected output..
But if i use print_r($ids);
i get,
Array ( [12] => Array ( [cat_id] => 12 [cat_parent_id] => 0 [cat_name] => Cars [cat_image] => dce08605333d805106217aaab7f93b95.jpg [cat_description] => Expensive and luxurious cars ) [13] => Array ( [cat_id] => 13 [cat_parent_id] => 0 .................................etc....
And
if i use print_r($ids[$category['cat_id']]);after for each loop
i get,
Array ( [cat_id] => 17 [cat_parent_id] => 13 [cat_name] => Hunter X Hunter [cat_image] => 746e05a7a629d53bc488115a75ee35d9.jpg [cat_description] => Story about hunter and combat )
The question is why do i get notice of undefined offset after using those,print_r($ids[$category[0]]);(as shown in last line of codes)..OR print_r($ids[$category[12]]); statements instead of expected output..
could you explain this please..
thanks
No comments posted yet
Your Answer:
Login to answer
189
40
Other forums
dinamic "textboxes"?
Ey all, my first post here, i hope its not a hard one
I display mysql results in a table
why this query can delete duplicates ?
why this query can delete duplicates ? Anybody can give me the detailed explanation ?
Tha
Multiple if statements
Ok so seems basic but for some reason I'm not doing it right. What I want is to be able to have 2 se
PHP/Database issue
My friend is helping me make a database where you go to a certain webpage of my site and the page wi
Mysql query, two times?
Hello to all,
I'm new to php coding and i like it alot. I need help with some noob stuff.
Redistributing dependent dlls
Hai all ,
I have created an application in VC++ using VS2008 in a development machine which r
login from external site
Hi my new experience begins, Now what i am trying to do is i make three pages, login.php logout.php
Error In Syntax
I got this error:
Code: Parse error: syntax error, unexpected '>' in /home/bucket/publ
some questions
Hello,
I am looking for the answers for following questions:
1) Does PHP support overl
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result
what is wrong with this
Code: [Select]<?php
if ($_SERVER['HTTP_REFERER'])
{