help with php
Posted on
16th Feb 2014 07:03 pm by
admin
It's not displaying or pulling anything out of the database.
Code: <html>
<head>
<title>Hale's Music World: Inventory Search Results</title>
</head>
<body>
<table border="1" cellpadding="0" cellspacing="0" style="border-collapse: collapse" width="56%" id="table1" height="129">
<tr>
<td bgcolor="#008000" colspan"3"> </td>
</tr>
<tr>
<td colspan="3">
<p align="center"><font size="5" color="#0000FF"><b>Inventory Search Results</font></td></tr>
<tr>
<td bgcolor="#008000" colspan="3"> </td>
</tr>
<tr>
<td width="33" align="center">
<font size="4" color="#008000">
<u>Artist</u></font></td>
<td width="33%" align="center">
<font size="4" color="#008000">
<u>Title</u></font></td>
<td width="33%" align="center">
<font size="4" color="#008000">
<u>Genre</u></font></td>
</tr>
<?php
$link = mysql_connect('localhost','halesuser','hales123db');
mysql_select_db("halesmusicworld", $link);
if ( isset( $_POST['Artist_Search'] ) AND $_POST['Artist_Search'] == 1 ) {
echo '1';
$artist_search = mysql_real_escape_string( $_POST["Artist_Search"] ) . '1' ;
$query = "select * from inventory where artist like '%" . $artist_search . "%'";
$result = mysql_query( "SELECT * FROM inventory", $link );
$num_rows = mysql_num_rows( $result );
echo 'Number of matching records=' . $num_rows . '<hr>';
}
if ( isset( $_POST['Title_Search'] ) AND $_POST['Title_Search'] == 2 ) {
echo '2';
$title_search = mysql_real_espace_string( $_POST["Title_Search"] ) . '2' ;
$query = "select * from inventory where title like '%" . $title_search . "%'";
$result = mysql_query( "SELECT * FROM inventory", $link );
$num_rows = mysql_num_rows( $result );
echo 'Number of matching records='. $num_rows . '<hr>';
}
if ( isset( $_POST['Genre_Search'] ) AND $_POST['Genre_Search'] == 3 ) {
echo '3';
$genre_search=$_POST ['Genre'] ;
$query= "select * from inventory where genre like '%".$genre_search."%'";
$query_results=mysql_query($query);
$match_results=mysql_num_rows($query_results);
echo 'Number of matching records='.$match_results. '<hr>';
}
echo '</tr>';
for ($i=0; $i < $match_results; $i++)
{
echo '<tr>';
$row=mysql_fetch_array($query_results);
echo '<td align="center">', ($row ['artist'] ), '</td>';
echo '<td align="center">', ($row ['title'] ), '</td>';
echo '<td align="center">', ($row ['genre'] ), '</td> </tr>';
}
?>
<tr>
<td bgcolor="#008000" colspan="3"> </td>
</tr>
</table>
<p align="center"><i>
<a href="HalesMusicWorld_Home.html">
<font face="Arial" size="5">
Return to </font></a><font face="Arial" size="5"> <a href="HalesMusicWorld_Home.html">HalesMusicWorld Home</font></i></p>
</body>
</html>
It gives me the following error message:
[/size][/font]Notice: Undefined variable: match_results in C:wampwwwinventory_search.php on line 61
I believe it has something to do with this line of code :
for ($i=0; $i < $match_results; $i++)
No comments posted yet
Your Answer:
Login to answer
237
54
Other forums
Variable passed to each() is not an array or object
Hi,
This is a email a friend type of form, and it isn't working anymore.
<?
PHP and Javascript
Hi Guys,
Im trying to load the contents of an html file into a text area for editing, this is
xml
<?php
echo "<h1>XML Articles</h1>";
$home
Using loop to count number of entries
I'm writing a program that must ask user to type in numbers. After each entry, the program has to re
Code working in IE but not FireFox
I created a dynamic navigation list for my website based off of a table in my database. The code is
Get ID from Database when Posting with a HTML Form
I have a form I am submitting to a MySql database. Each product has an ID # attached to it that auto
Renaming a file that a user uploads to site?
My site allows for registered users to upload images to the site under their own gallery. Currently
DateObject and Nulls
Hi all,
I have an array mapped to a value object. One of the items in the array is a PHP Date
Checking BOM Authorization Group
Hai Friends,
I have developed a mulitilevel BOM display report. End users have been assig
Relative path
I have a absolute path to an image - like so: C:/Program Files/Apache Software Foundation/Apache2.2/