Need help making login verification cleaner...

Posted on 16th Feb 2014 07:03 pm by admin

I use the below to verify user login. I first check the cookie for the id, ip and a unique id. If it's set then I move on to verifying that they all belong together. I usually copy and paste everything on a page that needs verification and I just edit the "we are good...." part.

Login verification
<?php
//Check to see if cookie is set
if (isset($_COOKIE['id']) && isset($_COOKIE['ip']) && isset($_COOKIE['uniqueid'])){

$cookieid = $_COOKIE['id'];
$cookieip = $_COOKIE['ip'];
$cookieuniqueid = $_COOKIE['uniqueid'];

require('header.php');

//Select id and loginip according to cookie uniqueid
$query = "SELECT * FROM user WHERE uniqueid = '$cookieuniqueid' LIMIT 1";

if ($result = mysql_query ($query)) {
while ($row = mysql_fetch_array ($result)) {
$id = $row['id'];
$uniqueid = $row['uniqueid'];
$ip = $row['ip'];
}
}

//Compare cookie ip and id with query loginip and id --- if cookies match database then we allow
if ($_COOKIE['id'] == $id && $_COOKIE['ip'] == $ip && $_COOKIE['uniqueid'] == $uniqueid) {
?>
we are good....
<?php

require('footer.php');
//End cookie compare
}
//Redirect to index if cookie compare fails
else {
header('Location: index.php');
}
//End cookie set
}
//Redirect to index if cookie is not set
else {
header('Location: index.php');
}
?>

I was wondering if there was a way for me to just do something like:

<?php
require('verify.php');
//If not logged in user wont see the below..
?>
Login user sees this

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Code: // Login ~ CHECKS