Attempt to assign property of non-object in...
Posted on
16th Feb 2014 07:03 pm by
admin
I'm having issues with the following function in PHP 5...
function getTreeWithChildren()
{
Did you know?Explore Trending and Topic pages for more stories like this.
$category_id = $this->fields['id'];
$parent_id = $this->fields['parent'];
$this->DB->build( array( 'select' => join(',', $this->getFields()),
'from' => $this->table,
'order' => $this->fields['sort']
) );
$this->DB->execute();
// create a pseudo root level object
$root = new stdClass;
$root->$category_id = 0;
$root->children = array();
$arr = array($root);
// populate array and create empty child array
while ($row = $this->DB->fetch()) {
$arr[$row->$category_id] = $row;
$arr[$row->$category_id]->children = array();
}
// build child data
foreach ($arr as $id => $row) {
if (isset($row->$parent_id))
$arr[$row->$parent_id]->children[$id] = $id;
}
return $arr;
}
I'm getting the error
QuoteAttempt to assign property of non-object in ... on line 391
which is...
$arr[$row->$category_id]->children = array();
I've tried typecasting "$this->DB->fetch()" to an object with...
while ($row = (object) $this->DB->fetch()) {
but get a maximum execution time exceeded error instead.
The code was originally written for PHP 4 so I suspect it might be a way the objects are handled and the use of stdClass()?
I'd be extremely grateful if somebody could give me pointers to make this PHP5 compatible (5.2.9)? Thanks in advance
No comments posted yet
Your Answer:
Login to answer
84
54
Other forums
Php - mysql store data and use it later?
Hi, i' making a login page at the moment, however my username + password is stored many different pl
php mysql query from input textbox
Hi,
I have a text box, in that i have given the mysql query. I can able to get the query in v
dropdown menu
Hello everbody,
I am php newbie.
I need to develop a program that once click the drop do
Help With editting and deleting form
Hallo !!
So look at this image :
http://img194.imageshack.us/img194/8272/snapshot5f.pn
I have a parse error in this query help..
Code: $query1="INSERT INTO `rating` (`item_name`, `rating`, `ip_address`, `date_rated`) VALUES
MySQL Primary key gap
Alright, so I have a table with 26 entries in it (id, filename, caption) for my image randomiser (ht
xml
<?php
echo "<h1>XML Articles</h1>";
$home
Wrong Info sent Using $get in form
Hi i have this code that i tried to make to send some info from one page to aother with lots of ppls
Pulling out some result data from MYSQL
Hey Guys,
I've built a PHP page that has a for just imagine something like registration form
Need help with cin setw
I made a program here is my code:
#include
#include
#i