Attempt to assign property of non-object in...


Posted on 16th Feb 2014 07:03 pm by admin

I'm having issues with the following function in PHP 5...

function getTreeWithChildren()
{
Did you know?Explore Trending and Topic pages for more stories like this.
$category_id = $this->fields['id'];
$parent_id = $this->fields['parent'];

$this->DB->build( array( 'select' => join(',', $this->getFields()),
'from' => $this->table,
'order' => $this->fields['sort']
) );
$this->DB->execute();


// create a pseudo root level object
$root = new stdClass;
$root->$category_id = 0;
$root->children = array();

$arr = array($root);

// populate array and create empty child array
while ($row = $this->DB->fetch()) {
$arr[$row->$category_id] = $row;
$arr[$row->$category_id]->children = array();
}

// build child data
foreach ($arr as $id => $row) {
if (isset($row->$parent_id))
$arr[$row->$parent_id]->children[$id] = $id;
}

return $arr;
}



I'm getting the error

QuoteAttempt to assign property of non-object in ... on line 391

which is...

$arr[$row->$category_id]->children = array();

I've tried typecasting "$this->DB->fetch()" to an object with...

while ($row = (object) $this->DB->fetch()) {

but get a maximum execution time exceeded error instead.

The code was originally written for PHP 4 so I suspect it might be a way the objects are handled and the use of stdClass()?

I'd be extremely grateful if somebody could give me pointers to make this PHP5 compatible (5.2.9)? Thanks in advance
No comments posted yet

Your Answer:

Login to answer
84 Like 54 Dislike
Previous forums Next forums
Other forums

Material xxx does not exist in plant xxx
Dear All,

I am working for a steel project which is repetitive manufacturing.

need help with this contact form
I made this form and I need it to read the data and write the data to a table and its not working ca

Help with PHP Email Script
Hi guys,

I'm a newbie to php and need help with the script below:

At the moment when I

foreach iterator
Hi Guys
Does the foreach loop have an inbuilt iterator ?

! = ''
In the following 'IF' statement if v_ompcat = PU for example then Oracle equates that 'IF' statement

please help me in this update statment
hi every one

if I have table and this data in it

id name
10

Querying info from one table based on info in another
Hi, I am currently trying to make a part for my user driven website where one user can subscribe to

How to get variable value on next page
Hello friends
i am working on payentry page ..there i have this code.........

Help with simple query
Hi,

I'm trying to do a Query with a Union where I want to print the number of rows $tc conta

array ...
hi
Code: function formatCategories($categories, $parentId)
{
// $navCat stores all child

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash