Can't seem to capture a variable in a chained select


Posted on 16th Feb 2014 07:03 pm by admin

I'm *this* close to having a chained select running but for some reason it doesn't seem to be picking up a variable.

Code: <?php

Did you know?Explore Trending and Topic pages for more stories like this.
require ('inc/connection.php');

//seeming that we are just submitting and refreshing to the one page we need to check if the post variable is set, and if so a couple of other variables are set
if(!isset($_POST['state'])) {
$next_dropdown = 0;
}
else {
//When set this variable reveals the next drop down menu
$next_dropdown = 1;
//this variable keeps the previous selection selected
$selected = $_POST['state'];
}
?>

<form name="form" method="post" action="">
<select name="state" style="font-size:20px;">
<option value="NULL">State</option>
<?php
$query = "SELECT id, name FROM state ORDER BY name ASC";
$result = mysql_query($query);
while($row = mysql_fetch_array($result))
{?>
<option value="<?php echo $row[0]; ?>" onClick="document.form.submit()" <?php if(isset($selected) && $row[0] == $selected) {echo "selected='selected'";} ?>><?php echo $row[1]; ?></option>n";
<?php }
echo '</form>n';
//this is where the other form will appear if the previous form is submitted
if($next_dropdown == 1) {?>
<form name="form2" action="" method="post">
<select name="city">
<option value="NULL">City</option>
<?php
$query2 = "SELECT * FROM city WHERE state_id = " . $row[0];
$result2 = mysql_query($query2);
while($row2 = mysql_fetch_array($result2))
{ ?>
<option value="<?php echo $row2[0]; ?>" onClick="document.form2.submit()"><?php echo $row2[1]; ?></option>
<?php }?>
</select>
</form>
<?php }
?>

The state drop down works fine. Once a state is selected, it will display the city drop down. However, the city drop down never populates. It's as though it forgets what $row[0] is. Any thoughts?
No comments posted yet

Your Answer:

Login to answer
83 Like 35 Dislike
Previous forums Next forums
Other forums

help with database debug pls
Parse error: syntax error, unexpected T_ELSE in /home/content/m/e/s/mesick/html/students/05/php/chec

Why does my crawler script suddenly end with no error?
Hi.

I have written a web crawler script. It will visit a large number of URL's with cURL.

storing video files into mysql in php
hi

i have my video files in my folder ,
i have to store the path of the videos into db an

Access database inside of a validation class
Hello,

For quite some time, I have been using functions to validate form input and access the

php file erros / need help please
Hello

Someone decoded a zend file for me.. after uploaded it on ftp i get some errors, i trye

Function module "DPS_CHECK_TABLE_EXISTS" not found (after OSS 1422843 impl)
Dear All,

I implemented Note OSS 1422843.

When i execute the new report RSPO20

2 things: enter doesn't work in IE & empty form
i have this search form that works well except for 2 things.

1) on IE when i hit enter instea

Using Curl_multi for processing multiple URLs
Hi,

I am at a loss as to how to implement this. I would like to be able to automatically assi

Connection Timeout
I'm using xmii 12.0

I'm calling a transaction as a web service from a windows application

parsing error
can anyone explain this syntax error:

Parse error: syntax error, unexpected T_IF

The e

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash