Can't seem to capture a variable in a chained select


Posted on 16th Feb 2014 07:03 pm by admin

I'm *this* close to having a chained select running but for some reason it doesn't seem to be picking up a variable.

Code: <?php

Did you know?Explore Trending and Topic pages for more stories like this.
require ('inc/connection.php');

//seeming that we are just submitting and refreshing to the one page we need to check if the post variable is set, and if so a couple of other variables are set
if(!isset($_POST['state'])) {
$next_dropdown = 0;
}
else {
//When set this variable reveals the next drop down menu
$next_dropdown = 1;
//this variable keeps the previous selection selected
$selected = $_POST['state'];
}
?>

<form name="form" method="post" action="">
<select name="state" style="font-size:20px;">
<option value="NULL">State</option>
<?php
$query = "SELECT id, name FROM state ORDER BY name ASC";
$result = mysql_query($query);
while($row = mysql_fetch_array($result))
{?>
<option value="<?php echo $row[0]; ?>" onClick="document.form.submit()" <?php if(isset($selected) && $row[0] == $selected) {echo "selected='selected'";} ?>><?php echo $row[1]; ?></option>n";
<?php }
echo '</form>n';
//this is where the other form will appear if the previous form is submitted
if($next_dropdown == 1) {?>
<form name="form2" action="" method="post">
<select name="city">
<option value="NULL">City</option>
<?php
$query2 = "SELECT * FROM city WHERE state_id = " . $row[0];
$result2 = mysql_query($query2);
while($row2 = mysql_fetch_array($result2))
{ ?>
<option value="<?php echo $row2[0]; ?>" onClick="document.form2.submit()"><?php echo $row2[1]; ?></option>
<?php }?>
</select>
</form>
<?php }
?>

The state drop down works fine. Once a state is selected, it will display the city drop down. However, the city drop down never populates. It's as though it forgets what $row[0] is. Any thoughts?
No comments posted yet

Your Answer:

Login to answer
83 Like 35 Dislike
Previous forums Next forums
Other forums

Format String help
I have a textbox where a person enters an application number. the application number is 10 characte

getting most records by count
Code: [Select]<?php

$connect = mysql_connect("localhost","dam

Curly Bracket Delimeters.
I'd always believed that the starting and ending delimeters in preg_ functions had to be the same ch

Lining up columns nicely.
Hello everyone, I'm having problems with making columns line up properly. Here is my code:

Email Form Syantax Issue 2
How to make this look FROM:"OUR TEAM" instead of FROM:abc@mail.com

$headers = "

phpmailer class & pop.gmail.com?
Code: <?php
$mail->IsSMTP();
$mail->Host = "pop.gmail.com";

How can I uploading Transactional Data from Legacy to New SAP system
Hell Gurus,

I am overwhelmed with questions on how to migrate huge volume of Sales Orders

replacements
I have a variable in my PHP script like

ASSFDDDDDDDDDDDDDASDDDDDDDDARYTRHKKHHHHHHHHHHH and p

using variables in another page
I have a test database set up on localhost. I have a form that I can type a name into, hit the butto

User feedback after MySQL query has been executed
Hi all, I've just registered on PHPFreaks because I've got a question that I simply can't work out b

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash