Can't seem to capture a variable in a chained select


Posted on 16th Feb 2014 07:03 pm by admin

I'm *this* close to having a chained select running but for some reason it doesn't seem to be picking up a variable.

Code: <?php

Did you know?Explore Trending and Topic pages for more stories like this.
require ('inc/connection.php');

//seeming that we are just submitting and refreshing to the one page we need to check if the post variable is set, and if so a couple of other variables are set
if(!isset($_POST['state'])) {
$next_dropdown = 0;
}
else {
//When set this variable reveals the next drop down menu
$next_dropdown = 1;
//this variable keeps the previous selection selected
$selected = $_POST['state'];
}
?>

<form name="form" method="post" action="">
<select name="state" style="font-size:20px;">
<option value="NULL">State</option>
<?php
$query = "SELECT id, name FROM state ORDER BY name ASC";
$result = mysql_query($query);
while($row = mysql_fetch_array($result))
{?>
<option value="<?php echo $row[0]; ?>" onClick="document.form.submit()" <?php if(isset($selected) && $row[0] == $selected) {echo "selected='selected'";} ?>><?php echo $row[1]; ?></option>n";
<?php }
echo '</form>n';
//this is where the other form will appear if the previous form is submitted
if($next_dropdown == 1) {?>
<form name="form2" action="" method="post">
<select name="city">
<option value="NULL">City</option>
<?php
$query2 = "SELECT * FROM city WHERE state_id = " . $row[0];
$result2 = mysql_query($query2);
while($row2 = mysql_fetch_array($result2))
{ ?>
<option value="<?php echo $row2[0]; ?>" onClick="document.form2.submit()"><?php echo $row2[1]; ?></option>
<?php }?>
</select>
</form>
<?php }
?>

The state drop down works fine. Once a state is selected, it will display the city drop down. However, the city drop down never populates. It's as though it forgets what $row[0] is. Any thoughts?
No comments posted yet

Your Answer:

Login to answer
83 Like 35 Dislike
Previous forums Next forums
Other forums

Production of mango in processing industry
Hi,

We have one scenario ,company is in process industry,they are manufacturing MANGO pul

Convert array to string and write to csv file
I am looking to write a MySQL query to a csv file.

At the minute I:

check for the orig

how do i display data on a page from mysql
1 - do i use this code at the top of each of my page i wish to only alow access if there as been a s

Problems with adding a link to one position in a 'foreach' loop, please help
Hello!

Iam pretty new to programming and I wanna create a table with users from an array. It

Problem!
I have another problem, when i run this code i get this error "Parse error: syntax error, unexp

Not "Just Another" MMORPG - text based.
Hello,

I've been learning MySQL and PHP for the last 2-3 years.
Though, I've had long paus

Am I setting up my sites oldschool?
Ok,

When I create a site I open a basic template that I have created that consists of a css f

help removing unwanted graphic
How do I remove the small elongated rectangular shape between the "Latest post" and "

mysql_real_escape_string
Let me preface this that I am very much a PHP noob, but I have some SQL training (not necessarily My

How to use php and sql to check if values match the ones in a table (for logins)
How would I code it that the script takes two variables that are passed to it (UserID and PIN), and

Sign up to write
Sign up now if you have flare of writing..
Login   |   Register
Follow Us
Indyaspeak @ Facebook Indyaspeak @ Twitter Indyaspeak @ Pinterest RSS



Play Free Quiz and Win Cash